Suggested languages for you:
|
|

## All-in-one learning app

• Flashcards
• NotesNotes
• ExplanationsExplanations
• Study Planner
• Textbook solutions

# Pythagorean Identities

Pythagorean identities are equations based on Pythagoras' theorem $$a^2 + b^2 = c^2$$. You can use this theorem to find the sides of a right-angled triangle. There are three Pythagorean identities.

Right-angled triangle used for the base of Pythagoras theorem

## The first Pythagorean identity

The first Pythagorean identity is $$\sin^2 \theta + \cos^2 \theta = 1$$. This can be derived using Pythagoras theorem and the unit circle.

Unit circle showing the derivation for the first Pythagorean identity

We know that $$a^2 + b^2 = c^2$$ so $$\sin^2 \theta + \cos^2 \theta = 1$$.

## The second Pythagorean identity

The second Pythagorean identity is $$\tan^2\theta + 1 = \sec^2\theta$$. This is derived by taking the first Pythagorean identity and dividing it by $$\cos^2\theta$$:

$\frac{\sin^2\theta}{\cos^2\theta} + \frac{\cos^2\theta} {\cos^2\theta} = \frac{1}{\cos^2\theta} .$

Remember that

$\frac{\sin\theta}{\cos\theta} = \tan\theta \mbox{ and } \frac{1}{\cos\theta} = \sec\theta.$

Simplifying this expression we get $$\tan^2\theta + 1 = \sec^2\theta$$.

## The third Pythagorean identity

The third Pythagorean identity is $$1 + \cot^2\theta = \csc^2\theta$$. This is derived by taking the first Pythagorean identity and dividing it by $$\sin^2\theta$$:

$\frac{\sin^2\theta}{\sin^2\theta} + \frac{\cos^2\theta} {\sin^2\theta} = \frac{1}{\sin^2\theta} .$

Remember that

$\frac{\cos\theta}{\sin\theta} = \cot\theta \mbox{ and } \frac{1}{\sin\theta} = \csc\theta.$

Now we can simplify this expression to $$1 + \cot^2\theta = \csc^2\theta$$.

## How to use Pythagorean identities

We will now look at three examples of using each of the Pythagorean identities to answer questions.

Simplify $$\sin x \cos^2 x = \sin x -1$$ and find the value of $$x$$: $$0 ＜ x ＜ 2\pi$$.

For this, we will need to use the first Pythagorean identity: $$\sin^2 \theta + \cos^2 \theta = 1$$ and rearrange it:

$\cos^2 x = 1 - \sin^2 x .$

We can now substitute $$1 - \sin^2 x$$ into the expression:

$\sin x \cos^2 x = \sin x(1 - \sin^2 x ).$

Simplifying this and setting it equal to the right hand side, we get

$\sin x - \sin^3 x = \sin x -1$

or

$-\sin^3 x = -1.$

So $$\sin x = 1$$ and $$x = \frac{\pi}{2}$$.

If $$\cos x = 0.78$$, what is the value of $$\tan x$$?

For this, we need to use the fact that $$\tan^2x + 1 = \sec^2x$$. We also know that

$\sec x = \frac{1}{\cos x}$

therefore

$\sec x = \frac{1}{0.78} = 1.282 .$

We can now substitute this value into the equation and find $$\tan x$$:

$\tan^2 x + 1 = (1.282)^2$

so

$\tan^2 x = (1.282)^2 -1$

and $$\tan x = 0.802$$.

Solve for $$x$$ between $$0^\circ$$ and $$180^\circ$$:

$\cot^2 (2x)+ \csc (2x) - 1 = 0.$

In this case, we need to use the third Pythagorean identity, $$1 + \cot^2\theta = \csc^2\theta$$.

If we rearrange this identity, we get $$\cot^2\theta = \csc^2\theta - 1$$. In this case $$\theta = 2x$$ and we can plug in this rearranged identity into our equation:

$\left( \csc^2(2x) - 1 \right) + \csc 2x - 1 = 0$

so

$\csc^2 2x + \csc 2x - 2 = 0.$

We can treat this as a quadratic that we can factorise into

$(\csc 2x + 2)(\csc 2x - 1) = 0.$

We can now solve this and get $$\csc 2x = -2$$ or $$\csc 2x = 1$$, so $$\sin 2x = -\frac{1}{2}$$ or $$\sin x = 1$$. Therefore $$2x = 210^\circ$$, $$330^\circ$$, $$90^\circ$$. and $$x = 45^\circ$$, $$105^\circ$$, $$165^\circ$$.

## Pythagorean Identities - Key takeaways

• The first Pythagorean identity is $$\sin^2 \theta + \cos^2 \theta = 1$$.

• The second Pythagorean identity is $$\tan^2\theta + 1 = \sec^2\theta$$.

• The third Pythagorean identity is $$1 + \cot^2\theta = \csc^2\theta$$.

• The first identity is derived from the Pythagorean theorem $$a^2 + b^2 = c^2$$ and the unit circle.

• The second and third identities are derived from the first identity.

The Pythagorean identities are derived from Pythagoras theorem and the unit circle.

They are expressions which are based on Pythagoras theorem and can be used to solve or simplify trigonometric equations.

sin^2(𝛉) +cos^2(𝛉) =1, tan^2(𝝷)+1=sec^2(𝝷) and 1+cot^2(𝝷)=csc^2(𝝷)

## Final Pythagorean Identities Quiz

Question

What theorem are Pythagorean identities based on?

Pythagoras Theorem

Show question

60%

of the users don't pass the Pythagorean Identities quiz! Will you pass the quiz?

Start Quiz

## Study Plan

Be perfectly prepared on time with an individual plan.

## Quizzes

Test your knowledge with gamified quizzes.

## Flashcards

Create and find flashcards in record time.

## Notes

Create beautiful notes faster than ever before.

## Study Sets

Have all your study materials in one place.

## Documents

Upload unlimited documents and save them online.

## Study Analytics

Identify your study strength and weaknesses.

## Weekly Goals

Set individual study goals and earn points reaching them.

## Smart Reminders

Stop procrastinating with our study reminders.

## Rewards

Earn points, unlock badges and level up while studying.

## Magic Marker

Create flashcards in notes completely automatically.

## Smart Formatting

Create the most beautiful study materials using our templates.