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Rational Expressions

Rational Expressions

Rational expressions are found in all sorts of areas of math and science. In fact, you might struggle to find any area of engineering that doesn't make use of special rational expressions called transfer functions. Seriously, they are everywhere! But what exactly is a rational expression? It may sound like a complicated concept, but really they have a simple definition.

Definition of Rational Expressions

What is the definition of rational expressions then? Well...

A rational expression is an expression whose numerator and denominator are polynomials.

From this definition, which of these do you think are rational expressions?

\( (1) \)\[ \frac{2x}{x+1} \]

\( (2) \)\[ \frac{x^3 + 3x^2 + x + 12}{x^2 + 3x + 5} \]

\( (3) \)\[ \frac{\sqrt{3x}}{4x^2} \]

\((1)\) and \( (2) \)! Did you get that right? Number \(3\) is not a rational expression because the numerator is not a polynomial.

Now that we've learned how to recognize rational functions, we should know how to categorize them. This isn't too tricky, as there are only two categories to remember: Proper and improper rational functions.

Recognize these terms from anywhere? Well, these are two categories of fractions as well!

With fractions, you might remember that a proper fraction has a greater degree in the denominator than the numerator, and that an improper fraction has a greater numerator than denominator.

\[ \frac{2}{3} \text{ is a Proper Fraction} \]

\[ \frac{3}{2} \text{ is an Improper Fraction} \]

Well, rational expressions are very similar. In fact, a proper rational expression has a greater degree denominator than numerator, and an improper rational expression has a greater degree in the numerator than in the denominator.

\[ \frac{2x^2 + 3}{3x^3 + 2x - 1} \text{ is a Proper Rational Expression} \]

\[ \frac{3x^3 + 2x^2 + x + 1}{x^2 + 2x + 4} \text{ is an Improper Rational Expression} \]

The degree of a polynomial is the highest power of any term in the polynomial.

Simplifying Rational Expressions

Sometimes, you might have a rational expression that is not in its most simple form. In cases like this, it is your job to simplify them. This usually entails cancelling common factors of the numerator and denominator.

Let's take, for example, the following rational expression.

\[ \frac{x(x+1)}{x(2x+7)} \]

What common factor do the numerator and denominator share? \( x \) of course! Just like when you are simplifying fractions, when you find a common factor between the numerator and denominator, you can take it out and cancel it:

\[ \frac{x(x+1)}{x(2x+7)} = \frac{\cancel{x}(x+1)}{\cancel{x}(2x+7)} .\]

So your simplified rational expression is

\[ \frac{(x+1)}{(2x+7)}. \]

Let's take a look at some more examples.

Simplify the following rational expressions.

(a)

\[ \frac{10(3x+2)(x-1)}{5(4x - 7)(x-1)} \]

(b)

\[ \frac{(2x-3)(x+4)}{(2x - 3)} \]

(c)

\[ \frac{(3x-10)}{2(3x-10)} \]

Solution:

(a)

The rational expression can be simplified by cancelling the common factors, \(5\) and \((x-1)\). That gives you

\[ \begin{align} \frac{10(3x+2)(x-1)}{5(4x - 7)(x-1)} &= \frac{5 \cdot 2(3x+2)(x-1)}{5(4x-7)(x-1)} \\ &=\frac{\cancel{5} \cdot2 (3x+2)\cancel{(x-1)}}{\cancel{5}(4x - 7)\cancel{(x-1)}}\\ &= \frac{2(3x+2)}{(4x - 7)} .\end{align} \]

(b)

The rational expression can be simplified by cancelling the common factor, \((2x-3)\), to get

\[\begin{align} \frac{(2x-3)(x+4)}{(2x - 3)} &= \frac{\cancel{(2x-3)}(x+4)}{\cancel{(2x - 3)}} \\ &= \frac{(x+4)}{1} \\ &= x+4 \end{align} \]

(c)

The rational expression can be simplified by cancelling the common factor, \((3x-10)\), to get

\[ \begin{align} \frac{(3x-10)}{2(3x-10)} &= \frac{\cancel{(3x-10)}}{2\cancel{(3x-10)}} \\ &= \frac{1}{2} .\end{align}\]

Factoring Rational Expressions

The examples above weren't too tricky to simplify. It was just a case of spotting the common factors in the numerator and denominator and cancelling them out. Well, rational expressions aren't always in that nice simple factored form. Luckily, this is something you can do yourself!

If you factor both the numerator and denominator polynomials of a rational expression, often you will find a common term between the two that you can cancel to simplify.

Let's try some examples. If you need your memory jogged on how to factor polynomials first, head over to our Factoring Polynomials explanation!

Factor, then simplify the following rational expressions.

(a)

\[ \frac{ x^2 -2x - 8 }{ x^2 + 5x + 6 } \]

(b)

\[ \frac{x^2 -2x - 3 }{x^2 -4x +3} \]

(c)

\[ \frac{x^3 - x}{ x^2 - x } \]

Solution:

(a)

By factoring the numerator and denominator, you can find the common factor of \((x+2)\). So

\[ \begin{align} \frac{ x^2 -2x - 8 }{ x^2 + 5x + 6 } &= \frac{(x+2)(x-4)}{(x+2)(x+3)} \\ &= \frac{\cancel{(x+2)}(x-4)}{\cancel{(x+2)}(x+3)} \\&= \frac{x-4}{x+3} .\end{align} \]

(b)

By factoring the numerator and denominator, you can find the common factor of \((x-3)\), so

\[ \begin{align} \frac{x^2 -2x - 3 }{x^2 -4x +3} &= \frac{(x+1)(x-3)}{(x-1)(x-3)} \\ &= \frac{(x+1)\cancel{(x-3)}}{(x-1)\cancel{(x-3)}} \\&= \frac{x+1}{x-1} .\end{align} \]

(c)

By factoring the numerator and denominator, you can find the common factors, \(x\) and \( (x-1)\). That gives you

\[ \begin{align} \frac{x^3 - x}{ x^2 - x } &= \frac{x(x^2-1)}{x(x - 1)} \\ &= \frac{x(x^2-1)}{x(x - 1)} \\ &= \frac{x(x+1)(x-1)}{x(x - 1)} \\ &= \frac{\cancel{x}(x+1)\cancel{(x-1)}}{\cancel{x}\cancel{(x - 1)}} \\ &= x + 1. \end{align} \]

Equivalent Rational Expressions

You may remember working with equivalent fractions. That is, fractions with different denominators that are equal in value. For instance

\[\frac{2}{4} = \frac{4}{8}.\]

Starting with one side of the equation, you can rewrite it in steps until you get to the other side. For this fraction you can start with the right hand side and show that

\[\begin{align} \frac{4}{8} &= \frac{2\cdot 2 }{2 \cdot 2 \cdot 2} \\ &= \frac{\cancel{2}\cdot 2}{2\cdot 2\cdot \cancel{2}}\\ &= \frac{ 2}{2 \cdot 2 } \\ &= \frac{2}{4}. \end{align}\]

Notice that you stopped cancelling before you got all the way done cancelling everything. This is because the goal is to make it look like the left hand side of the equation, not to cancel everything.

Equivalent rational expressions function in a very similar way. Start with one side, and work with it until you can get it to look like the other side.

Let's take a look at an example.

Are the following pairs of rational expressions equivalent to one another?

(a) \[ \frac{x^2 + 2}{x^2 - 4}, \text{ and } \frac{2x^2 + 4}{2x^2 - 8} \]

(b) \[\frac{(x-2)}{(x-2)(x+4)}, \text{ and } \frac{(x+4)}{(x+4)^2}\]

(c) \[\frac{x^2 + 2x + 1}{x}, \text{ and } \frac{x^2 + 2x + 1}{3x}\]

Solution:

(a)

It is a good idea to start with the one that is more complicated looking. Then

\[ \begin{align} \frac{2x^2 + 4}{2x^2 - 8} &=\frac{2(x^2+2)}{2(x^2-4)} \\&= \frac{\cancel{2}(x^2+2)}{\cancel{2}(x^2-4)} . \end{align}\]

Since you have reached the other expression, you are done and the rational expressions are equivalent.

(b)

Another way to do this is to simplify both rational expressions and see if you get the same thing. The numerator and denominator of the first rational expression have a common factor of \((x-2)\), so

\[\begin{align} \frac{(x-2)}{(x-2)(x+4)} &= \frac{\cancel{(x-2)}}{\cancel{(x-2)}(x+4)} \\ &= \frac{1}{(x+4)}. \end{align}\]

The numerator and denominator of the second rational expression have a common factor of \((x+4)\), so

\[ \begin{align} \frac{(x+4)}{(x+4)^2} &= \frac{(x+4)}{(x+4)(x+4)} \\ &= \frac{1\cdot \cancel{(x+4)}}{(x+4)\cancel{(x+4)}} \\ &= \frac{1}{(x+4)}. \end{align}\]

Since you got the same thing after simplifying both of them, they are equivalent rational expressions.

(c)

The two rational expressions have the same numerator but different denominators, therefore they are not equal and so aren't equivalent rational expressions.

Examples with Rational Expressions

Let's look at some more examples to practice everything.

Are the following terms rational expressions?

(a) \[ \frac{4x^2 - 2}{x} \]

(b) \[ \frac{2}{2x - 4} \]

(c) \[2x + 5\]

Solution:

(a) Yes, since the numerator and denominator are polynomials.

(b) Yes, since the numerator and denominator are polynomials.

(c) Yes, as it can be written as

\[\frac{2x+5}{1}\]

Let's take a look at categorizing rational expressions as proper or improper.

Categorize the following rational expressions as proper or improper.

(a) \[ \frac{2x + 10}{x^2 - x + 20} \]

(b) \[ \frac{x^2}{10x} \]

(c) \[ \frac{4x^4 + 3x^3 + \frac{1}{2}x^2 + x}{x^2 - 3x + 2} \]

(d) \[ \frac{1}{x+3} \]

Solution:

(a) Proper, since the degree of the numerator is \(1\) which is less than the degree of the denominator which is \(2\).

(b) Improper, since the degree of the numerator is greater than the degree of the denominator.

(c) Improper, since the degree of the numerator is greater than the degree of the denominator.

(d) Proper, since the degree of the numerator is less than the degree of the denominator.

What about simplifying rational expressions?

Simplify the following rational expressions.

(a) \[ \frac{(x-2)(x+3)(x-1)}{x(x-1)(x-2)} \]

(b) \[ \frac{x(3x + 5)}{x(4x - 1)} \]

(c) \[ \frac{(x-5)(x^3 + 2x^2 + 3)}{x^3 + 2x^2 + 3} \]

Solution:

(a)

The numerator and denominator have common factors, \((x-1)\) and \((x-2)\). These can be cancelled to simplify, giving you

\[ \begin{align} \frac{(x-2)(x+3)(x-1)}{x(x-1)(x-2)} &=\frac{\cancel{(x-2)}(x+3)\cancel{(x-1)}}{x\cancel{(x-1)}\cancel{(x-2)}} \\ &= \frac{x+3}{x} . \end{align}\]

(b)

The numerator and denominator have a common factor, \(x\)). This can be cancelled to simplify, giving you

\[ \begin{align} \frac{x(3x + 5)}{x(4x - 1)} &= \frac{\cancel{x}(3x + 5)}{\cancel{x}(4x - 1)}\\ &= \frac{3x+5}{4x-1}. \end{align}\]

(c)

The numerator and denominator have a common factor, \((x^3 + 2x^2 + 3\)). This can be cancelled to simplify, giving you

\[\begin{align} \frac{(x-5)(x^3 + 2x^2 + 3)}{x^3 + 2x^2 + 3} &= \frac{(x-5)\cancel{(x^3 + 2x^2 + 3)}}{\cancel{x^3 + 2x^2 + 3}} \\ &= x-5. \end{align}\]

Let's take a look at another example.

By first factoring them, simplify the following rational expressions.

(a) \[ \frac{2x^2 + 3 + 1}{2x+1} \]

(b) \[ \frac{x^2+6x+9}{x^2 + x - 6} \]

(c) \[ \frac{3x^3 + 8x^2 + 5x}{x^3 + 8x^2 + 7x} \]

Solutions:

(a)

By factoring the numerator and denominator, you can find the common factor, \((2x+1)\). Obtain the simplified rational expression by cancelling the common factor:

\[\begin{align} \frac{2x^2 + 3 + 1}{2x+1} &= \frac{(2x+1)(x+1)(2x+1)}{2x+1} \\ &= \frac{\cancel{(2x+1)}(x+1)}{\cancel{2x+1}} \\ &=x+1 .\end{align}\]

(b)

By factoring the numerator and denominator, you can find the common factors, \(2\) and \((x+3)\). Obtain the simplified rational expression by cancelling the common factor:

\[\begin{align} \frac{x^2+6x+9}{x^2 + x - 6} &= \frac{(x+3)^2}{(x+3)(x-2)} \\ &= \frac{(x+3)^{\cancel{2}}}{\cancel{(x+3)}(x-2)} \\ &= \frac{x+3}{x-2}. \end{align}\]

(c)

By factoring the numerator and denominator, you can find the common factors, \(x\) and \((x+1)\). Obtain the simplified rational expression by cancelling the common factor.

\[ \begin{align} \frac{3x^3 + 8x^2 + 5x}{x^3 + 8x^2 + 7x} &= \frac{x(3x + 5)(x+1)}{x(x+7)(x+1)} \\ &= \frac{\cancel{x}(3x + 5)\cancel{(x+1)}}{\cancel{x}(x+7)\cancel{(x+1)}} \\ &=\frac{3x + 5}{x+7} .\end{align} \]

Rational Expressions - Key takeaways

  • Rational expressions are terms with polynomials as the numerator and denominator.
  • Proper rational expressions have a lower degree numerator than denominator.
  • Improper rational expressions have a higher degree numerator than denominator.
  • Rational expressions can be simplified by factorizing the numerator and denominator, then cancelling any common factors.

Frequently Asked Questions about Rational Expressions

Rational expressions can be simplified by factorizing the numerator and denominator, then cancelling any common factors.

A rational expression is a term with polynomials as the numerator and denominator.

Rational expressions do not have domains as they are not functions. However, if a rational expression is part of a function, the domain can be found by finding the roots of the denominator. The domain will not include these numbers as it is impossible to divide by zero.

Find the roots of the denominator, i.e. the values of input for which the denominator is equal to 0.

Final Rational Expressions Quiz

Question

What is a rational expression?

Show answer

Answer

A rational expression is an algebraic fraction whose numerator and denominator are both polynomials.

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Question

Find the LCM of 

(x²+2x+1),(x²+5x+4) and y³

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Answer

(x+1)(x+4)y³

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Question

Find the LCM of 

50x²,xy5 and 75x2z

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Answer

150x²y5z

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Question

Find the LCM of 

4,9x,18y

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Answer

36xy

Show question

Question

What is a rational expression?

Show answer

Answer

A rational expression is an algebraic fraction whose numerator and denominator are both polynomials.

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Question

Find the LCM of 

50x,xy4 and 75x2z


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Answer

150x2y4z

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Question

Find the LCM of (x²-1), (x²+5x+4) and y

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Answer

(x-1)(x+1)(x+4)y

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Question

Find the LCM of 

2z, 4x and 6xy


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Answer

12xyz

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Question

What is a rational expression?

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Answer

A rational expression is an expression whose numerator and denominator are polynomials.

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Question

Which of these is a rational expression?

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Answer

\(\dfrac{2x^2+2}{x-1}\).

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Question

Which of these is a rational expression?

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Answer

\[ \frac{2x^2 + x + 3}{4x + 2} \]

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Question

Which of these is NOT a rational expression?

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Answer

\[ 5 \]

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Question

When do you use the long division method?

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Answer

When we have a situation where neither the numerator nor the denominator of the rational expression can be factorized and there are no common factors. 

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Question

Rational expressions can be treated like fractions. 

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Answer

True

Show question

Question

Is the following a proper or improper rational expression?

\[ \frac{2x^3 -10x + 4}{2x -8} \]

Show answer

Answer

Improper, the order of the numerator is greater than the order of the denominator.

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Question

Is the following rational expression proper or improper?

\[ \frac{2x}{(x-4)(x+7)} \]

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Answer

Proper, the order of the numerator is less than the order of the denominator.

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Question

Simplify the following rational expression.

\[ \frac{(x-2)(x+3)(x-10)}{(x-2)(x-10)} \]


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Answer

\[ x+3 \]

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Question

Simplify the following rational expression.

\[ \frac{2x}{x(x-7)} \]

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Answer

\[ \frac{2}{x-7} \]

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Question

Which of these is NOT a rational expression?




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Answer

\[ \frac{1}{5 + \frac{1}{x}} \]

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Question

Simplify the following rational expression.

\[ \frac{x^2 + 4x - 21}{x^3 - 8x^2 +15x} \]

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Answer

\[ \frac{x+7}{x(x-5)} \]

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Question

Simplify the following rational expression.

\[ \frac{x^3 + 2x^2 + x}{x+1} \]

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Answer

\[ x^2 + x \]

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Question

Simplify the following rational expression.

\[ \frac{x^2 - 3x - 10}{x^2 - 6x + 5} \]

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Answer

\[ \frac{x+2}{x-1} \]

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Question

Simplify the following rational expression.

\[ \frac{(x+2)(x-4)}{x(x+2)(x-4)} \]

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Answer

\[ \frac{1}{x} \]

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Question

What is a rational expression?

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Answer

A rational expression is an algebraic fraction whose numerator and denominator are both polynomials.

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Question

State whether the following statement is true or false:

A mixed expression is a combination of monomials and rational expressions.

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Answer

True

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Question

State whether the following statement is true or false:

A mixed expression must contain exactly 1 monomials.

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Answer

False

Show question

Question

State whether the following statement is true or false:

A mixed expression must contain exactly 1 polynomial.

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Answer

False

Show question

Question

Find the LCM of 

25x, 45x²y

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Answer

225x²y

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Question

Find the LCM of 

3x², 45xy²

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Answer

45x²y²

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Question

What is a proper rational expression?

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Answer

A proper rational expression is a rational expression with a lower order numerator than denominator.

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Question

What is an improper rational expression?

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Answer

An improper rational expression is a rational expression with a higher order numerator than denominator.

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