Suggested languages for you:

Americas

Europe

|
|

# Fluids

## Want to get better grades?

• Flashcards
• Notes
• Explanations
• Study Planner
• Textbook solutions

Lerne mit deinen Freunden und bleibe auf dem richtigen Kurs mit deinen persönlichen Lernstatistiken

Nie wieder prokastinieren mit unseren Lernerinnerungen.

Fluid is a term that refers to any form of matter which flows. In the science community, fluids embody a wide range of concepts. We demonstrate many of these concepts subconsciously in our everyday lives. For example, adding ice to our warm drinks displays the concept of density. A hot bath after a long day demonstrates Archimedes' principle. Pouring milk into a glass verse water demonstrates the viscosity. These are only a few examples of small-minute tasks we perform every day that demonstrate fluids. Therefore, keeping these examples in mind, let's use this article as a starting point in understanding some different concepts related to fluids.

## Fluid Physics Definition

Fluids, i.e., liquids or gases, are systems of particles that easily move and change position.

Fluids are substances with no distinct shape and change easily relative to the presence of external pressure.

The study of fluids is known as fluid mechanics. Fluid mechanics focus on the forces that arise due to the behavior of fluids. Fluid mechanics is divided into two parts: fluid statics and fluid dynamics. Fluid statics is the study of incompressible fluids at rest. In contrast, fluid dynamics is the study of fluids in motion.

## Properties of Fluid

To study the behavior and forces produced by fluids, we look at properties such as density, temperature, pressure, viscosity, specific volume, and specific gravity.

• Density, $$\rho$$, is the amount of mass present in a substance per unit volume. Its corresponding formula is $$\rho=\frac{m}{V}$$, where $$m$$ is mass and $$V$$ is volume.

• Pressure, $$P$$, is the force exerted on a fluid per unit area.

• Pressure, due to gravity, exerted on a fluid at any point is called Hydrostatic pressure. The formula corresponding to hydrostatic pressure is $$P= {\rho}gh$$, where $$P$$ is fluid pressure, $$\rho$$ is density, $$g$$ is the acceleration due to gravity, and $$h$$ is the depth of the fluid.

• Gauge Pressure is the difference between total pressure and atmospheric pressure. Its corresponding formula is $$P_G=P_T - P_A$$, where $$P_G$$ represents gauge pressure, $$P_T$$ represents total pressure, and $$P_A$$ represents atmospheric pressure.

• Absolute pressure is the sum of gauge pressure and atmospheric pressure.

• Temperature is a thermodynamic property indicating how hot or cold a fluid is. Temperature refers to the average kinetic energy within a substance.

• Viscosity is a fluid's resistance to motion. If a fluid has a negligible viscosity or no viscosity, it is said to be an inviscid fluid.

• Specific Volume is the ratio of a substance's volume to mass. It is the reciprocal of density. Its corresponding formula is $$v=\frac{V}{m}=\frac{1}{\rho}$$.

• Specific Weight is the weight per unit volume. Its corresponding formula is $$\gamma =\rho{g}$$. Note that this property varies with temperature.

## Fluid Categories

Fluids are broken down into multiple categories depending on different properties, such as flow or viscosity. Flow refers to the action of moving.

 Type Description Steady or Unsteady Steady flows indicate that conditions such as velocity and pressure vary but do not change with respect to time. In contrast, unsteady suggests that, at some point, these conditions change with respect to time. Uniform or Non-uniform Uniform flow indicates that the velocity of a fluid has the same magnitude and direction at all points within the fluid. Non-uniform flow indicates that velocity does not have the same magnitude or direction at all points within the fluid. Compressible or Incompressible Compressible fluids are fluids whose volume and density change due to pressure. Incompressible fluids are fluids whose volume and density do not change due to pressure. Viscous or Non-viscous Viscous refers to a substance with a thicker consistency due to internal friction. Viscous fluids resist motion. Non-viscous fluids move easily and have a thinner consistency. Newtonian or Non-Newtonian Newtonian fluids have constant viscosity, while non-Newtonian fluids do not have constant viscosity.

## Key Concepts of Fluids

Besides being aware of fluid properties and categories, one should also be aware of two key concepts associated with fluids.

1. Buoyancy and Archimedes' principle.

2. Conservation of energy and the Bernoulli equation.

### Buoyancy and Archimedes Principle

Buoyancy is the tendency for objects to float within a fluid.

Buoyancy is the upward force that fluids exert on a fully or partially submerged object.

On a microscopic level, fluids consist of atoms that are bound together. Due to a fluid's ability to move, when an object is placed inside a fluid, the atoms are pushed aside and bend around the object. Since the fluid wants to be back in its original state, the atoms exert interatomic electric forces to push against the object, which causes an upward buoyant force. To fully understand buoyancy, we must discuss Archimedes' principle, which is the physical law of buoyancy.

Archimedes' principle states that the upward buoyant force on a fully or partially submerged object is equal to the weight of the fluid that the object displaced.

To better understand this principle, let's look at the following example of a cube submerged in water, where we have simplified the forces due to the pressure of the water into a single downward force and a single upward force.

Force is equal to pressure, $$P$$ times the area, $$A$$, where the pressure is being exerted.

$$F=PA.$$

Now we know that pressure is equal to the density of the fluid times gravity times the height of the fluid.

$$P=\rho_\mathrm{f}gh.$$

Therefore, we can express the force acting on the top and bottom of the cube as follows:

$$F_1=\rho_\mathrm{f}gh_1A,$$

$$F_2=\rho_\mathrm{f}gh_2A.$$

To find the buoyant force, we must find the difference between the force acting on the top and the force acting on the bottom.

$$F_2-F_1=\rho_\mathrm{f}g(h_2-h_1)A.$$

where $$h_2-h_1$$ is the height of the cube. When we multiply this by the area of the face of the cube, $$A$$, we get the volume of the cube, $$V_\mathrm{f}$$, or in this case, the amount of water displaced by the cube. Consequently, we can derive the following equation for the buoyant force,

$$F_\mathrm{b}=\rho_\mathrm{f}V_\mathrm{f}g,$$

and as we know that mass is equal to density times volume, we can substitute mass into the equation. This yields the equation

$$F_\mathrm{b}=m_\mathrm{f}g,$$ and since weight is equal to mass times gravity, the above result indicates that the buoyant force is equal to the weight of the displaced fluid, as stated by Archimedes' principle.

### Conservation of Energy and the Bernoulli Equation

An important equation associated with fluids is Bernoulli's equation which describes the conservation of energy in fluid flow. This equation emphasizes the relationship between velocity and pressure. It states that when discussing moving fluids, a point where velocity is low means that the pressure is high, and a point where velocity is high, pressure is low.

$$\text{Bernoulli's Equation} \rightarrow P_1 + \frac{1}{2}\rho{v_1}^2 + {\rho}gh_1=P_2 + \frac{1}{2}\rho{v_2}^2 + {\rho}gh_2.$$

To help our understanding, let's look at the following example and derive the Bernoulli equation.

To derive this equation, three assumptions are made.

1. A streamlined flow indicates that all particles in the fluid follow the same path.

2. Constant density which indicates an incompressible fluid.

3. No viscosity while moving.

In order to proceed, we must calculate the work required to move a volume of fluid from one position to another. Note that the fluid at point one travels a distance of $$\Delta{l}_1$$ while the fluid at point two travels a distance of $$\Delta{l}_2$$.

Step 1: Calculate the work done on the fluid at point one at its cross-sectional area, $$A_1$$, by the fluid to the left of it. The fluid to the left of point one forces the fluid to move toward point two.

$$W_1= F_1\Delta{l}_1= P_1A_1\Delta{l}_1.$$

Step 2: Calculate the work done at point two on its cross-sectional area, $$A_2$$. Work here will be negative because the force acting on the fluid is opposite to the motion of the fluid.

$$W_2= -F_2\Delta{l}_2= -P_2A_2\Delta{l}_2.$$

Step 3: Calculate the work done by the fluid against gravity.

$$W_3= -mg(y_2-y_1)=-mg\Delta{y}.$$

Step 4: Calculate the total work done on the system.

\begin{align}W_T&= W_1 + W_2 + W_3\\W_T&= P_1{A_1}\Delta{l}_1 -P_2{A_2}\Delta{l}_2 -mg\Delta{y}\\\end{align}

Now recall the work-energy theorem, which states that the total kinetic energy, where kinetic energy is $$K=\frac{1}{2}m{v^2}$$, of a system, is equal to the total work done on that system. Hence, this yields the equation

$$\frac{1}{2}m{v_2}^2-\frac{1}{2}m{v_1}^2=P_1A_1\Delta{l}_1 -P_2A_2\Delta{l}_2 -mg\Delta{y},$$

where we can write mass in terms of density and volume using the density equation, $$\rho=\frac{m}{V}\implies m=\rho{V}$$, and replace the term $$A{\Delta{l}}$$ by $$V$$ because the product of those two terms gives us volume.

$$\frac{1}{2}\rho{V}{v_2}^2 - \frac{1}{2}\rho{V}{v_1}^2 = P_1{V}-P_2{V} - \rho{V}g\Delta{y}.$$

The $$V's$$ will cancel out, thus yielding the equation,

$$P_1 + \frac{1}{2}\rho{v_1}^2 + {\rho}gh_1=P_2 + \frac{1}{2}\rho{v_2}^2 + {\rho}gh_2,$$

which is Bernoulli's equation. However, two key points to recognize and understand are that this equation only holds true if our assumptions hold true and that since we used the work-energy theorem, we can logically deduce that this equation is essentially derived as a result of the conservation of energy.

## Shearing Stress in Fluids

When parallel objects slide past one another, this action is known as shearing. This phenomenon occurs in fluids and results in shearing stress.

Shearing stress is a force acting parallel to the surface, which causes a breakdown of structure.

Shearing stress is one of two types of stress fluids undergo. In physics, stress refers to a force per unit area acting on an infinitesimal surface. Stresses are vector quantities and are divided into normal stresses and tangential stresses. Normal stresses include pressures that act inward and perpendicular to the surface. Tangential stresses include shear stresses. The main reason shear stresses are present in fluids is friction due to viscosity. Fluids cannot resist shear stress. This means that when shear stress is applied to a fluid at rest, the fluid moves as it is unable to remain at rest.

## Experiments in Fluids

Reading scientific jargon to fully understand scientific concepts, like fluids, is sometimes hard to wrap your mind around. Hence, let's discuss two easy experiments that can help you better understand concepts like Archimedes' principle and the principle behind Bernoulli's equation.

### Archimedes' Principle

To visualize Archimedes' principle, take a glass of warm water and put a grape in the water. The grape sinks because it is denser than the water. However, if we add salt to the water, the grape begins to float. Recall that Archimedes' principle states that if an object's weight is more than its own volume when placed in a fluid, the object sinks. Adding salt to the water increases the water's mass per unit volume until it is equal to or greater than the density of the grape, thus allowing the grape to float.

### Bernoulli's Equation

To demonstrate the principles behind Bernoulli's equation, we can perform some balloon magic. This idea requires us to blow up two balloons of the same size and attach strings of the same length to each balloon. Using tape, we attach the balloons to the underside of the top part of our door frame. Make sure the balloons are separated by some distance. Finally, take a hairdryer and blow a steady stream of air in between the balloons using both the low and high settings. What do you see? On the low setting, the balloons most likely did not move too much. However, on the high setting, did you notice that the balloons move toward one another without being touched? This effect is Bernoulli's principle, which demonstrates that the air surrounding the balloons is exerting the same amount of pressure on all sides of the balloon. By blowing more forcible air between the balloons, an area of low pressure is created. Faster-moving air creates less pressure. Therefore, the pressure between the balloons decreased compared to when balloons were at rest with no airflow separating them. As a result, the balloons move toward each other as high pressure pushes low pressure.

## Examples of Fluid

As we discussed fluids and some key corresponding concepts, let's complete some quick examples to drive home what we've learned.

An object has a mass of $$15\,\mathrm{kg}.$$ If it occupies a volume of $$4.6\,\mathrm{m^3}$$ calculate the density of this object.

\begin{align}\rho&=\frac{m}{V},\\\rho&=\frac{15\,\mathrm{kg}}{4.6\,\mathrm{m^3}},\\\rho&=3.3\,\mathrm{\frac{kg}{m^3}}.\\\end{align}

The density of this particular object is $$3.3\,\mathrm{\frac{kg}{m^3}}.$$

Let's try a slightly more complicated example.

On one end of a pipe, point A, water flows at a speed of $$6\,\mathrm{\frac{m}{s}}$$ with a pressure of $$400,000\,\mathrm{Pa}$$. At the other end, point B, the water flows at a speed of $$12\,\mathrm{\frac{m}{s}}$$. Calculate the water pressure at point B. Density of water is $$1000\,\mathrm{\frac{kg}{m^3}}$$.

Fig. 3 - Using Bernoulli's equation to calculate the water pressure on one end of a pipe.

Based on this problem, we know that we will need the Bernoulli equation, $$P_1 + \frac{1}{2}\rho{v_1}^2 + {\rho}gh_1=P_2 + \frac{1}{2}\rho{v_2}^2 + {\rho}gh_2$$, because we are dealing with pressure and velocity. However, since the height of the pipe is not given, we can assume that height does not change, thus cancel allowing those terms to cancel out, which yields the equation, $$P_1 + \frac{1}{2}\rho{v_1}^2 _1=P_2 + \frac{1}{2}\rho{v_2}^2.$$ Now, inserting our given values, we can calculate the pressure at point B as follows. \begin{align}P_1 + \frac{1}{2}\rho{v_1}^2 &=P_2 + \frac{1}{2}\rho{v_2}^2,\400,000\,\mathrm{Pa})+\frac{1}{2}\left(1000\,\mathrm{\frac{kg}{m^3}}\right)\left(6\,\mathrm{\frac{m}{s}}\right)^2&=P_2+\frac{1}{2}\left(1000\,\mathrm{\frac{kg}{m^3}}\right)\left(12\,\mathrm{\frac{m}{s}}\right)^2,\\418,000&=P_2 +72,000,\\P_2&= 346,000\,\mathrm{Pa}.\\\end{align} Therefore, the water pressure at point B is \(346,000.

## Fluids - Key takeaways

• Fluids are substances with no distinct shape and change easily relative to the presence of external pressure.
• The study of fluids is known as fluid mechanics, which focuses on the forces that arise due to the behavior of fluids.
• To study the behavior and forces produced by fluids, we look at properties, such as density, temperature, pressure, viscosity, specific volume, and specific gravity.
• Fluids are broken down into multiple categories depending on different properties such as flow or viscosity.
• Two key concepts associated with fluids are:
1. Buoyancy and Archimedes' principle.
2. Conservation of energy and the Bernoulli equation.
• Shearing stress is a force acting parallel to the surface, which causes a breakdown of structure.

## References

1. Fig. 1 - Archimedes' principle, StudySmarter Originals.
2. Fig. 2 - Bernoulli's equation, StudySmarter Originals.
3. Fig. 3 - Pipe and pressure, StudySmarter Originals.

Fluids are substances with no distinct shape and change easily relative to the presence of external pressure.

Examples of fluids can refer to worked examples involving calculations or actually examples of fluids like liquids or gases.

The concept of fluids refers to systems of particles that easily move and change position which we study and is known as fluid mechanics.

To study the behavior and forces produced by fluids, we look at properties such as density, temperature, pressure, viscosity, specific volume, and specific gravity.

## Fluids Quiz - Teste dein Wissen

Question

True/False: Fluids are substances with distinct shapes and do not change easily relative to the presence of external pressure.

False.

Show question

Question

The study of fluids at rest corresponds to which of the following?

Fluid Statics.

Show question

Question

The study of fluids in motions corresponds to which of the following?

Fluid Dynamics.

Show question

Question

The formula, $$\rho=\frac{m}{V}$$, corresponds to which of the following fluid properties?

Density.

Show question

Question

Fill in the Blank

____ pressure is the difference between total pressure and atmospheric pressure.

Gauge pressure.

Show question

Question

When velocity and pressure vary but do not change with respect to time, this corresponds to what type of fluid flow?

Show question

Question

Constant viscosity is indicative of which of the following fluids?

Newtonian.

Show question

Question

Fill in the Blank

____is the upward force that fluids exert on a fully or partially submerged object.

Buoyancy.

Show question

Question

Archimedes' principle states that the upward buoyant force on a fully or partially submerged object is _____.

equal to the weight of the fluid that the object displaced.

Show question

Question

Bernoulli's equation describes the relationship between which of the following?

Velocity and pressure.

Show question

Question

Which of the following equations depicts Bernoulli's equation?

$$P_1 + \frac{1}{2}\rho{v_1} + {\rho}gh_1=P_2 + \frac{1}{2}\rho{v_2} + {\rho}gh_2.$$

Show question

Question

What conservation theory corresponds to Bernoulli's equation?

Conservation of energy.

Show question

Question

Shear stress is a type of ____ stress.

Tangential.

Show question

Question

A grape sits at the bottom of a glass of water. Adding salt to the water, causes the grape to float. This demonstrates which of the following fluid concepts?

Archimedes' principle.

Show question

Question

An object has a mass of $$10\,\mathrm{kg}.$$ If it occupies a volume of $$5\,\mathrm{m^3}$$ calculate the density of this object.

$$2\,\mathrm{\frac{kg}{m^3}}.$$

Show question

Question

On one end of a pipe, point A, water flows at a speed of $$5\,\mathrm{\frac{m}{s}}$$  with a pressure of $$400,000\,\mathrm{Pa}$$. At the other end, point B, the water flows at a speed of $$10\,\mathrm{\frac{m}{s}}$$. Calculate the water pressure at point B.  Density of water is $$1000\,\mathrm{\frac{kg}{m^3}}$$.

$$P_2=362,500\,\mathrm{Pa}.$$

Show question

60%

of the users don't pass the Fluids quiz! Will you pass the quiz?

Start Quiz

## Study Plan

Be perfectly prepared on time with an individual plan.

## Quizzes

Test your knowledge with gamified quizzes.

## Flashcards

Create and find flashcards in record time.

## Notes

Create beautiful notes faster than ever before.

## Study Sets

Have all your study materials in one place.

## Documents

Upload unlimited documents and save them online.

## Study Analytics

Identify your study strength and weaknesses.

## Weekly Goals

Set individual study goals and earn points reaching them.

## Smart Reminders

Stop procrastinating with our study reminders.

## Rewards

Earn points, unlock badges and level up while studying.

## Magic Marker

Create flashcards in notes completely automatically.

## Smart Formatting

Create the most beautiful study materials using our templates.