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Organic Chemistry
Found in: Page 379

Short Answer

Question: Draw a stepwise, detailed mechanism for the following reaction.


See the step by step solution

Step by Step Solution

Step-by-Step SolutionStep 1: Reaction of ether with strong acid

The strong acids will protonate the oxygen atom of ether. Then a most stable carbocation intermediate is formed during this process.

Step 2: Ether with tertiary butyl group

When an ether molecule consists of a tertiary butyl group in it, then the reaction of ether with strong acid leads to an elimination reaction from the tertiary butyl radical.

Step 3: Explanation

The given acid is a strong acid, and it protonates the given ether and forms a tertiary butyl carbocation intermediate. This tertiary butyl carbocation further undergoes an elimination reaction and forms the products.

The mechanism of the reaction is as shown:

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