Question: Draw a stepwise, detailed mechanism for the following reaction.
The strong acids will protonate the oxygen atom of ether. Then a most stable carbocation intermediate is formed during this process.
When an ether molecule consists of a tertiary butyl group in it, then the reaction of ether with strong acid leads to an elimination reaction from the tertiary butyl radical.
The given acid is a strong acid, and it protonates the given ether and forms a tertiary butyl carbocation intermediate. This tertiary butyl carbocation further undergoes an elimination reaction and forms the products.
The mechanism of the reaction is as shown:
Question: Answer each question using the ball-and-stick model of compound A.
a. Give the IUPAC name for A, including R,S designations for stereogenic centers.
b. Classify A as a alcohol.
c. Draw a stereoisomer for A and give its IUPAC name.
d. Draw a constitutional isomer that contains an OH group and give its IUPAC name.
e. Draw a constitutional isomer that contains an ether and give its IUPAC name.
f. Draw the products formed (including stereochemistry) when A is
treated with each reagent:  NaH;  ;  , pyridine;
 HCl;  ,pyridine;  TsCl, pyridine.
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