Draw the alkynes formed when each dihalide is treated with excess base.
The products formed after the treatment is shown below:
is a strong base. When used in excess, it tends to abstract all the protons since, in these substrates, two leaving groups are present. As a result, the elimination product formed gives an alkyne.
Removal of excess hydrogens gives rise to the elimination product. Different types of hydrogens give different types of products. But here, different types of hydrogens give a single product due to the formation of alkyne.
Based on the steps, the products formed after the treatment with s shown below:-
Given that an E2 reaction proceeds with anti periplanar stereochemistry, draw the products of each elimination. The alkyl halides in (a) and (b) are diastereomers of each other. How are the products of these two reactions related? Recall from Section 3.2A that is a phenyl group, a benzene ring bonded to another group.
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