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Q.52

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Organic Chemistry
Found in: Page 328

Short Answer

Under certain reaction conditions, 2,3-dibromobutane reacts with two equivalents of base to give three products, each of which contains two new bonds. Product A has two sp hybridized carbon atoms, product B has one sp hybridized carbon atom, and product C has none. What are the structures of A, B, and C?

The structures A, B, and C, are shown below:-

See the step by step solution

Step by Step Solution

Concentration of the base

The base is taken here in two equivalents, and as a result, two times elimination reaction will occur as it will abstract two hydrogens.

Types of  hydrogens

The presence of different types of hydrogens results in different products.

Representation of different types of hydrogens

Two types of hydrogens are there; hence two different products will be formed. But here, three different products will be formed due to three different mechanistic approaches towards its product formation.

Observation of the structures

The structure contains two sp hybridized carbons

The structure contains only one sp hybridized carbons.

The structure contains no sp hybridized carbons

Based on all the given points. the structures A, B, and C, are drawn below:-

Representation of the final products

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