Four times a number decreased by 6 is less than $-2$. Define a variable, write an inequality, and solve for the number.

The addition property of inequalities states that if the same number is added to each side of a true inequality, the resulting inequality is also true that is:

(i) If $a>b$, then $a+c>b+c$.

(ii) If $a<b$, then $a+c<b+c$.

The division property of inequalities states that if both sides of the inequality are divided by a positive number the sign of the inequality remains the same and if both sides of the inequality are divided by a negative number then the sign of the inequality changes that is:

(i) If $a>b$ and c is a positive number then $\frac{a}{c}>\frac{b}{c}$.

(ii) If $a<b$ and c is a positive number then $\frac{a}{c}<\frac{b}{c}$.

(ii) If $a>b$ and c is a negative number then $\frac{a}{c}<\frac{b}{c}$.

(iv) If $a<b$ and c is a negative number then $\frac{a}{c}>\frac{b}{c}$.

It is given that Four times a number decreased by 6 is less than $-2$.

Let x denote the number.

Therefore, the inequality is:

$4x-6<-2$

The solution of the given inequality $4x-6<-2$ is:

$$\begin{gathered} 4x-6<-2 \\ 4x-6+6<-2+6\left(\text{by using addition property of inequality}\right) \\ 4x<4 \\ \frac{4x}{4}<\frac{4}{4}\left(\text{by using division property of inequality}\right) \\ x<1 \end{gathered}$$

Therefore, the solution of the inequality $4x-6<-2$ is $x<1$.

Therefore, the number is less than 1.