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Q48.

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Found in: Page 637

### Algebra 2

Book edition Middle English Edition
Author(s) Carter
Pages 804 pages
ISBN 9780079039903

# Solve each equation.$\sqrt{2x+1}=3$

The solution is $x=4$.

See the step by step solution

## Step 1. Given Information.

Given, to solve the equation $\sqrt{2x+1}=3$.

## Step 2. Calculation.

Simplifying the equation:

$\begin{array}{l}\sqrt{2x+1}=3\\ {\left(\sqrt{2x+1}\right)}^{2}={\left(3\right)}^{2}\\ 2x+1=9\\ 2x=9-1\\ 2x=8\\ x=\frac{8}{2}\\ x=4\end{array}$

Checking if the value of x satisfies the equation:

$\begin{array}{l}\sqrt{2x+1}=3\\ \sqrt{2\left(4\right)+1}=3\\ \sqrt{8+1}=3\\ \sqrt{9}=3\\ 3=3\end{array}$

Hence the value of x satisfies the equation.

## Step 3. Conclusion.

Hence, the solution is x=4.