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Q48.

Expert-verifiedFound in: Page 637

Book edition
Middle English Edition

Author(s)
Carter

Pages
804 pages

ISBN
9780079039903

**Solve each equation.**

** **

**$\sqrt{2x+1}=3$**

The solution is** $x=4$.**

Given, to solve the equation $\sqrt{2x+1}=3$.

Simplifying the equation:

$\begin{array}{l}\sqrt{2x+1}=3\\ {\left(\sqrt{2x+1}\right)}^{2}={\left(3\right)}^{2}\\ 2x+1=9\\ 2x=9-1\\ 2x=8\\ x=\frac{8}{2}\\ x=4\end{array}$

Checking if the value of *x* satisfies the equation:

$\begin{array}{l}\sqrt{2x+1}=3\\ \sqrt{2\left(4\right)+1}=3\\ \sqrt{8+1}=3\\ \sqrt{9}=3\\ 3=3\end{array}$

Hence the value of *x* satisfies the equation.

Hence, the solution is x=4.

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