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Q. 36

Expert-verified
Calculus
Found in: Page 499
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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Short Answer

Find the exact value of the arc length of each function f(x) on [a, b] by writing the arc length as a definite integral and then solving that integral.

f(x)=2(1-x)3/2+3, a,b=-2,0

The arc length is 227(28)3/2-227(10)3/2.

See the step by step solution

Step by Step Solution

Step 1. Given information. 

Consider the given function f(x)=2(1-x)3/2+3, a,b=-2,0.

Step 2. Use arc length formula.

The formula for a function to find the arc length from x=a to x=b is given by ab1+(f'(x))2dx.

Step 3. Find the arc length.

Arc length=-201+ddx(2(1-x)3/2+3)2dx=-201+(232(1-x)1/2(-1)+0)2dx=-201+-3(1-x)1/2)2dx=-201+9(1-x)dx=-2010-9xdx

Step 4. Simply obtained integral by simple substitution.

Substitute 10-9x=u, dx=-19du into -2010-9xdx.

2810-u9du=-192810udu=--191028udu=19102823u3/2=1923u3/21028=227(28)3/2-227(10)3/2

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