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Q. 23

Expert-verified
Calculus
Found in: Page 210
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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Short Answer

Find the derivatives of the functions in Exercises 21–46. Keep in mind that it may be convenient to do some preliminary algebra before differentiating.

f(x)=x(3x2+1)9

The required answer is (3x2+1)9+54x2(3x2+1)8

See the step by step solution

Step by Step Solution

Step 1. Given Information 

The given function is f(x)=x(3x2+1)9

Step 2. Calculation 

Differentiate both the sides with respect to x, we get,

f'(x)=ddx(x)(3x2+1)9+xddx(3x2+1)9 =(3x2+1)9+x9(3x2+1)9-1ddx(3x2+1)=(3x2+1)9+x9(3x2+1)8ddx3x2+ddx1=(3x2+1)9+x9(3x2+1)83(2x)=(3x2+1)9+54x2(3x2+1)8

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