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Q. 3

Expert-verifiedFound in: Page 119

Book edition
1st

Author(s)
Peter Kohn, Laura Taalman

Pages
1155 pages

ISBN
9781429241861

If $f$ is a continuous function, what can you say about $\underset{x\to 1}{\mathrm{lim}}f\left(x\right)?$

It can be concluded that there is no hole in the graph of the function at$x=c.$

A continuous function is given.

A function $f$ is continuous at $x=c$ whenever $f\left(c\right)$ is defined, $f$ has a limit as $x\to c$ and the value of the limit and the value of the function agree. This guarantees that there is not a hole or jump in the graph of $f$at $x=c.$

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