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Q. 31

Expert-verified
Calculus
Found in: Page 772
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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Short Answer

Use Cartesian coordinates to express the equations for the parabolas determined by the conditions specified in Exercises 22–31.

r=α1+sinθ

The equation of the parabola is x2=-2yα+α2.

See the step by step solution

Step by Step Solution

Step 1. Given information.

The given polar equation is r=α1+sinθ.

Step 2. Conversion.

Converting the polar into cartesian co-ordinates,

r=α1+sinθr(1+sinθ)=αr+rsinθ=αx2+y2+r·yr=α since r=x2+y2 and rsinθ=yx2+y2+y=α

Step 3. Final answer.

On simplifying the equation,

x2+y2+\noty-\noty=α-yx2+y2=α-yx2+y22=(α-y)2x2+y2=α2+y2-2yαx2+y2-y2=α2+y2-2yα-y2x2=-2yα+α2

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