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Q. 59

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Calculus
Found in: Page 773
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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Short Answer

Prove that for an ellipse or a hyperbola the eccentricity is given by

e= the distance between the foci the distance between the vertices

Hence proved.

See the step by step solution

Step by Step Solution

Step 1. Given information.

We are given,

e= the distance between the foci the distance between the vertices

Step 2. Explanation.

Now,

Let the foci of the ellipse are ±A2-B2,0. Formula for the distance =x1-x22+y1-y22 Distance =A2-B2--A2-B22+(0-0)2 Distance =2A2-B22 Thus the distance between the foci is, Distance =2A2-B2We have the eccentricity e=A2-B2A Then e=2A2-B22A Thus, e= the distance between foci the distance between the vertices

Hence proved.

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