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Q. 23

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Calculus
Found in: Page 692
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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Short Answer

In Exercises 23–32 we ask you to give Lagrange’s form for the corresponding remainder, R4(x)

cosx

The required answer is R4(x)=-sinc120x5

See the step by step solution

Step by Step Solution

Step 1. Given Information

The given function is f(x)=cosx

Step 2. Explanation

Using the Lagrange form of remainder, we have,

Rn(x)=fn+1(c)(n+1)!xn+1R4(x)=f5(c)5!x5

Now, we will find fifth derivative of the function.

f1(x)=-sinxf2(x)=-cosxf3(x)=sinxf4(x)=cosxf5(x)=-sinx

Thus, we get,

R4(x)=-sinc120x5

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