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Expert-verified Found in: Page 417 ### Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861 # For each function u(x) in Exercises 9–12, write the differential du in terms of the differential dx.$u\left(x\right)=\frac{1}{x}$

The differential du in terms of the differential dx is $du=-\frac{1}{{x}^{2}}dx$.

See the step by step solution

## Step 1. Given Information

For given function u(x) we have to write the differential du in terms of the differential dx.

$u\left(x\right)=\frac{1}{x}$

## Step 2. Now finding the differential du in terms of the differential dx.

$u\left(x\right)=\frac{1}{x}\phantom{\rule{0ex}{0ex}}u\left(x\right)={x}^{-1}\phantom{\rule{0ex}{0ex}}\frac{du}{dx}=-1{x}^{-2}\phantom{\rule{0ex}{0ex}}\frac{du}{dx}=-\frac{1}{{x}^{2}}\phantom{\rule{0ex}{0ex}}du=-\frac{1}{{x}^{2}}dx$ ### Want to see more solutions like these? 