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Q. 22

Expert-verified
Calculus
Found in: Page 824
Calculus

Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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Short Answer

In Exercises 22–29 compute the indicated quantities when u=(2,1,3), v=(4,0,1), and w=(2,6,5)

u×v and v×u

The value of u×v=1i+14j-4k and localid="1649397999598" v×u=-1i-14j+4k

See the step by step solution

Step by Step Solution

Step 1. Given Information 

In Exercises 22–29 compute the indicated quantities whenu=(2,1,3), v=(4,0,1), and w=(2,6,5)

We have to find the value of u×v and v×u

Step 2. Firstly finding the value of u×v

The value of vectors u=(2,1,3), v=(4,0,1)

The cross product of u×v

localid="1649398046712" u×v=detijk21-3401

Step 3. Now solving the matrix.

u×v=detijk21-3401u×v=((1)(1)(-3)(0))i+((2)(1)(-3)(4))j+((2)(0)(1)(4))ku×v=(1+0)i+(2+12)j+(04)ku×v=1i+14j-4k

Step 4. Now finding the value of v×u

The value of vectors u=(2,1,3), v=(4,0,1)

The cross product of v×u=detijk40121-3

Step 5. Now solving the matrix. 

v×u=detijk40121-3v×u=((0)(-3)(1)(1))i+((4)(-3)(1)(2))j+((4)(1)(0)(2))kv×u=(0-1)i+(-12-2)j+(40)kv×u=-1i-14j+4k

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