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Q 50.

Expert-verified
Found in: Page 801

### Calculus

Book edition 1st
Author(s) Peter Kohn, Laura Taalman
Pages 1155 pages
ISBN 9781429241861

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# Find a unit vector in the direction opposite to .

The required vector is .

See the step by step solution

## Step 1. Given information.

The given vector is:

## Step 2. Find the norm of the vector.

Therefore, the norm of the given vector is $\sqrt{50}$.

## Step 3. Find the vector.

We know that the vector in the direction of v is $\frac{1}{||\mathbit{v}||}\left(\mathbf{-}\mathbit{v}\right)$. Here a is the magnitude of the given vector and the negative sign shows the direction opposite to .

The required vector is:

role="math" localid="1649521227299"

Therefore, the unit vector in the direction opposite to is .

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