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Q60E

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Discrete Mathematics and its Applications
Found in: Page 204
Discrete Mathematics and its Applications

Discrete Mathematics and its Applications

Book edition 7th
Author(s) Kenneth H. Rosen
Pages 808 pages
ISBN 9780073383095

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Short Answer

Suppose we have three men m1,m2, and m3 and three women w1,w2, and w3 . Furthermore, suppose that the preference rankings of the men for the three women, from highest to lowest, are m1:w3,w1,w2;m2:w1,w2,w3;m3:w2,w3,w1 and the preference rankings of the women for the three men, from highest to lowest, are w1:m1,m1,m3;w2:m2,m1,m3;w3:m3,m2,m1 . For each of the six possible matchings of men and women to form three couples, determine whether this matching is stable.

First matching: m1w1,m2w2,m3w3 is stable.

Second matching: m1w1,m2w3,m3w2 is not stable.

Third matching: m1w2,m2w1,m3w3 is not stable.

Fourth matching: m1w2,m2w3,m3w1 is not stable.

Fifth matching: m1w3,m2w1,m3w2 is stable.

Sixth matching: m1w3,m2w2,m3w1 is not stable.

See the step by step solution

Step by Step Solution

Step 1:

We have given three men: m1,m2,m3 and three women w1,w2,w3 .

For stable matching, we have:

m1:w3>w2>w1m2:w1>w2>w3m3:w2>w3>w1

And

w1:m1>m2>m3w2:m2>m1>m3w3:m3>m2>m1

Step 2:

Now, we will have six possible matching; we will check whether they are stable or unstable.

First matching: m1w1,m2w2,m3w3 .

This is stable because all the women assigned their preferred partners.

Second matching: m1w1,m2w3,m3w2 .

This is not stable because m2 prefers w2 over his current partner and w2 prefers m2 over her current partner.

Third matching: m1w2,m2w1,m3w3 .

This is not stable because m1 prefers w1 over his current partner and w1 prefers m1 over her current partner.

Step 3:

Fourth matching: m1w2,m2w3,m3w1 .

This is not stable because m1 prefers w1 over his current partner and w1 prefers m1 over her current partner.

Fifth matching: m1w3,m2w1,m3w2 .

This is stable because all the men assigned their preferred partners.

Sixth matching: m1w3,m2w2,m3w1 .

This is not stable because m3 prefers w3 over his current partner and w3 prefers m3 over her current partner.

Step 4:

Hence, we have

First matching: m1w1,m2w2,m3w3 is stable.

Second matching: m1w1,m2w3,m3w2 is not stable.

Third matching: m1w2,m2w1,m3w3 is not stable.

Fourth matching: m1w2,m2w3,m3w1 is not stable.

Fifth matching: m1w3,m2w1,m3w2 is stable.

Sixth matching: m1w3,m2w2,m3w1 is not stable.

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