• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q37E

Expert-verified
Discrete Mathematics and its Applications
Found in: Page 344
Discrete Mathematics and its Applications

Discrete Mathematics and its Applications

Book edition 7th
Author(s) Kenneth H. Rosen
Pages 808 pages
ISBN 9780073383095

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Let a be an integer and d be a positive integer. Show that the integers q and r with a=dq+r and 0r<d which were shown to exist in Example 5, are unique.

The integers r and Q are unique.

See the step by step solution

Step by Step Solution

Step 1: Identification of the given data

The given data can be listed below as:

  • The value of the first integer is a.
  • The value of the positive integer is d.
  • The value of the second integer is q.
  • The value of the third integer is r.

Step 2: Significance of an integer

The integer is described as the whole number which does not provide a fractional value. The integer also does not have a fractional component.

Step 3: Determination of the uniqueness of the integers

Let the equation of the integer a can be expressed as:

a=dQ+R

Here, a is the value of the first integer and d is the value of the positive integer.

Here, Qq,0R<d and Rr then the above equation can be expressed as:

dq+r=dQ+Rd(Qq)=rR

It has been assumed that r>R without the loss of the generality. Moreover, 0<r-R<d and hence r-R is not divisible by d.

Now, if the above equation gets equal to zero, then Q=q and R=r becomes a contradiction. Hence, r and Q are described as distinct.

Thus, the integers r and Q are unique.

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.