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Expert-verified Found in: Page 590 ### Discrete Mathematics and its Applications

Book edition 7th
Author(s) Kenneth H. Rosen
Pages 808 pages
ISBN 9780073383095 # Which projection mapping is used to delete the first, second, and fourth components of a 6-tuple?

The resultant answer is $${P_{3,\;5,\;6}}$$.

See the step by step solution

## Step 1: Given data

6-tuple is given.

## Step 2: Concept of sets

The concept of set is a very basic one.

It is simple; yet, it suffices as the basis on which all abstract notions in mathematics can be built. $$A$$ set is determined by its elements.

If $$A$$ is a set, write $$x \in A$$ to say that $$x$$ is an element of $$A$$.

## Step 3: Simplify the expression

Consider the set of 6-tuple $$(A,B,C,D,E,F)$$.

If we apply the $${P_{3,\;5,\;6}}$$ then we will get the set $$(C,E,F)$$, which does not contain first, second and fourth component.

Therefore, we apply the $${P_{3,\;5,\;6}}$$ to delete first, second and fourth component. ### Want to see more solutions like these? 