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Q15E
Expert-verifiedWhich projection mapping is used to delete the first, second, and fourth components of a 6-tuple?
The resultant answer is \({P_{3,\;5,\;6}}\).
6-tuple is given.
The concept of set is a very basic one.
It is simple; yet, it suffices as the basis on which all abstract notions in mathematics can be built. \(A\) set is determined by its elements.
If \(A\) is a set, write \(x \in A\) to say that \(x\) is an element of \(A\).
Consider the set of 6-tuple \((A,B,C,D,E,F)\).
If we apply the \({P_{3,\;5,\;6}}\) then we will get the set \((C,E,F)\), which does not contain first, second and fourth component.
Therefore, we apply the \({P_{3,\;5,\;6}}\) to delete first, second and fourth component.
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