• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Deutsch (DE)
Deutsch (UK)
Deutsch (US)

Americas

Europe

Answers without the blur. Sign up and see all textbooks for free! → Illustration

Q1E

Expert-verified
Discrete Mathematics and its Applications
Found in: Page 581
Discrete Mathematics and its Applications

Discrete Mathematics and its Applications

Book edition 7th
Author(s) Kenneth H. Rosen
Pages 808 pages
ISBN 9780073383095

Answers without the blur.

Just sign up for free and you're in.

Register for Free I’ll do it later
Illustration

Short Answer

To determine list of the ordered pairs in the relation R from A={0,1,2,3,4} to B={0,1,2,3}, where (a,b)∈R if and only if lcm(a,b)=2.

R={(1,2),(2,1)}

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :
TABLE OF CONTENTS

Step 1: Given data

A={0,1,2,3,4} and B={0,1,2,3}

Step 2: Concept used ordered pair

An ordered pair (a,b) is a pair of elements associated in such a way that order matters. That is, the ordered pair (a,b) is different from (b,a)unlessa=b.

Step 3: Solve for relation

Ordered pairs are formed from set A and B.

R={(1,2),(2,1)}

Most popular questions for Math Textbooks

Display the table produced by applying the projection \({P_{1,2,4}}\) to Table 8.

An example of a relation on a set that is neither symmetric and anti symmetric.

Find the lexicographic ordering of the bit strings 0, 01, 11, 001, 010, 011, 0001, and 0101 based on the ordering \(0 < 1\).

To prove the closure with respect to the property. Of the relation \(R = \{ (0,0),(0,1),(1,1),(2,2)\} \) on the set \(\{ 0,1,2\} \) does not exist if . is the property" has an odd number of elements."

Exercises 34–37 deal with these relations on the set of real numbers:

\({R_1} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a > b} \right\},\) the “greater than” relation,

\({R_2} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a \ge b} \right\},\) the “greater than or equal to” relation,

\({R_3} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a < b} \right\},\) the “less than” relation,

\({R_4} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a \le b} \right\},\) the “less than or equal to” relation,

\({R_5} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a = b} \right\},\) the “equal to” relation,

\({R_6} = \left\{ {\left( {a,\;b} \right) \in {R^2}|a \ne b} \right\},\) the “unequal to” relation.

34. Find

(a) \({R_1} \cup {R_3}\).

(b) \({R_1} \cup {R_5}\).

(c) \({R_2} \cap {R_4}\).

(d) \({R_3} \cap {R_5}\).

(e) \({R_1} - {R_2}\).

(f) \({R_2} - {R_1}\).

(g) \({R_1} \oplus {R_3}\).

(h) \({R_2} \oplus {R_4}\).
Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Math Textbooks

Decision Maths

Read explanation

Calculus

Read explanation

Probability and Statistics

Read explanation

Statistics

Read explanation

Mechanics Maths

Read explanation

Geometry

Read explanation

Pure Maths

Read explanation

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.