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Q18E

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Essential Calculus: Early Transcendentals
Found in: Page 209
Essential Calculus: Early Transcendentals

Essential Calculus: Early Transcendentals

Book edition 2nd
Author(s) James Stewart
Pages 830 pages
ISBN 9781133112280

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Short Answer

Sketch the graph of \(f\) by hand and use your sketch to find the absolute and local maximum and minimum values of \(f\). (Use the graphs and transformations of Sections 1.2.)

18. \(f(t) = \cos t,\;\frac{{ - 3\pi }}{2} \le t \le \frac{{3\pi }}{2}\)

The absolute and local maximum occurs at \(t = 0\). The absolute and local minimum occurs at \(t = \pm \pi \).

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Step by Step Solution

Step 1: Given data

The given function is \(f(t) = \cos t,\frac{{ - 3\pi }}{2} \le t \le \frac{{3\pi }}{2}\).

Step 2: Concept of Differentiation

Differentiation is a method of finding the derivative of a function. Differentiation is a process, where we find the instantaneous rate of change in function based on one of its variables.

Step 3: Sketch the graph of the function

First draw the graph of the function \(f(t) = \cos t\) as shown below in Figure:

Since the function is restricted to \(\frac{{ - 3\pi }}{2} \le t \le \frac{{3\pi }}{2}\), draw the graph of the function in the closed interval of \(\left( {\frac{{ - 3\pi }}{2},\frac{{3\pi }}{2}} \right)\) as shown below in Figure 2 :

Generally the cosine curve attains the maximum at even multiples of \(\pi \) and attains the minimum at odd multiples of \(\pi \) as shown in Figure 1. According to the given interval, from Figure 2, it is observed that the cosine curve attains an absolute maximum at \(t = 0\) and attains an absolute minimum at \(t = \pm \pi \). Therefore, the absolute maximum occurs at \(t = 0\). Since any absolute maximum can be a local maximum, the local maximum is \(f(0) = 1\).

Similarly, the absolute minimum occurs at \(t = \pm \pi \). Since any absolute minimum can be a local minimum, the local minimum is \(f( \pm \pi ) = - 1\).

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