Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration


Essential Calculus: Early Transcendentals
Found in: Page 369
Essential Calculus: Early Transcendentals

Essential Calculus: Early Transcendentals

Book edition 2nd
Author(s) James Stewart
Pages 830 pages
ISBN 9781133112280

Answers without the blur.

Just sign up for free and you're in.


Short Answer

Sketch the region enclosed by the given curves and

find its area.

14. y = cosx, y = 2 - cosx, 0≤x≤2𝛑

The Area\( = 4\pi \)

See the step by step solution

Step by Step Solution

The given curves

Graph is shown,

Substitute the integral to find the area

\(y = \cos x\) is below for the entire interval. Subtract from the other function in the integral to find the area.

\(A{\rm{ }} = _0^{2\pi }(2 - \cos x - \cos x)dx = \;\;\;0_0^{2\pi }(2 - 2\cos x)dx\)

\( = (2x - 2\sin x)_0^{2\pi }\)

\( = 4\pi - 0 - (0 - 0)\)

\( = 4\pi \)

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.