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Q14E
Expert-verifiedSketch the region enclosed by the given curves and
find its area.
14. y = cosx, y = 2 - cosx, 0≤x≤2𝛑
The Area\( = 4\pi \)
Graph is shown,
\(y = \cos x\) is below for the entire interval. Subtract from the other function in the integral to find the area.
\(A{\rm{ }} = _0^{2\pi }(2 - \cos x - \cos x)dx = \;\;\;0_0^{2\pi }(2 - 2\cos x)dx\)
\( = (2x - 2\sin x)_0^{2\pi }\)
\( = 4\pi - 0 - (0 - 0)\)
\( = 4\pi \)
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