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Q1E
Expert-verifiedsuppose that \(\mathop {lim}\limits_{\left( {x,y} \right) \to \left( {3,1} \right)} f(x,y) = 6\) . What can you say about the value of \(f(3,1)\)? What if f is continuous?
The value of\(f(3,1)\)is\(6\). If the function f is continuous then, \(f(3,1) = 6\).
Suppose the function f is a real function on a subset of the real numbers and let c be a point in the domain of f. then f is continuous at c if \(\mathop {\lim }\limits_{x \to c} f(x) = f(c)\).
We are given that \(\mathop {\lim }\limits_{(x,y) \to (3,1)} f(x,y) = 6\)
Here, \((x,y)\) approaches to \((3,1)\). Thus the value is \(6\).
According to the definition of the continuous function, if f is continuous then the value of \(f(3,1) = 6\) .
Therefore, The value of\(f(3,1)\)is\(6\). If the function f is continuous then, \(f(3,1) = 6\).
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