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Q26E

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Essential Calculus: Early Transcendentals

Found in: Page 632

Book edition 2nd

Author(s) James Stewart

Pages 830 pages

ISBN 9781133112280

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Short Answer

Determine the set of points at which the function is continuous. \(f\left( {x,y,z} \right) = \sqrt {y{\rm{ - }}{x^2}} {l_n}z\)

\(\left\{ {\left( {x,y,z} \right)\left| {y \ge {x^2},z{\rm{ > }}0} \right|} \right\}\)

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step-1: Finding Restriction on Domain

The function f is a composition of elementary function and is therefore continuous on its domain.

The square root function is defined so long as the expression inside the radical is non-negative.

Therefore, one restriction on the domain is \(y{\rm{ - }}{x^2} \ge 0\)or simply \(y \ge {x^2}\).

Step-2: Finding Another Restriction

Another restriction is z>o since the natural log function is only defined for positive real numbers.

The another restriction on the domain of f and hence, the set of aa points for which f is continuous is the combination of these two restrictions.

Hence, \(\left\{ {\left( {x,y,z} \right)\left| {y \ge {x^2},z{\rm{ > }}0} \right|} \right\}\)

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