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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 77
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

x0In problems 33-40, Solve the equation given in Problem 2.

y-4x-12dx-dy=0

14logy-4x-3y-4x+1-x=Cand

See the step by step solution

Step by Step Solution

Solving the given equation

The given equation is,

y-4x-12dx-dy=0

Simplify the above equation,

y-4x-12dx=dydydx=y-4x-12······1

Let,

t=y-4x-1dtdx=dydx-4dydx=dtdx+4

Substitute the t=y-4x-1 and dydx=dtdx+4 in the equation (1),

dtdx+4=t2

Simplify the above equation,

dtdx=t2-4

Cross multiplication on both sides in the above equation,

dtt2-4=dx

Integrating

Taking integration of both sides in the above equation

dtt2-22=dx

One knows that,

dxx2-a2=12alogx-ax+a+c

Solve the above equation,

122logt-2t+2=x+c14logt-2t+2-x=c

Finding the solution

Substitute the t=y-4x-1 in the above equation,

14logy-4x-1-2y-4x-1+2-x=c

Simplify the above equation,

14logy-4x-3y-4x+1-x=C

Also, note that x0 is a solution.

Hence the solution is 14logy-4x-3y-4x+1-x=C and x0

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