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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 271
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

In Problems 19–24, convert the given second-order equation into a first-order system by setting v=y’. Then find all the critical points in the yv-plane. Finally, sketch (by hand or software) the direction fields, and describe the stability of the critical points (i.e., compare with Figure 5.12).

d2ydt2+y=0

The point is an unstable saddle point (0, 0).

See the step by step solution

Step by Step Solution

Step 1: Find the critical point

Here the equation is d2ydt2+y=0.

Put v=y'andv'=y''

Then the given system can be written as:

y''=-yv'=-y

For critical points equate the system equal to zero.

v=0-y=0y=0

So, the critical point is (0, 0).

The phase plane equation is:

dvdy=-yvvdv=-ydyv2+y2=c

Step 2: Sketch

This is the required result.

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