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Q8E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 271
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

In Problems 7–9, solve the related phase plane differential equation (2), page 263, for the given system.

dxdt=x2-2y-3,dydt=3x2-2xy

The solution is x3-x2y-y-2=c .

See the step by step solution

Step by Step Solution

Step 1: Find phase plane equation

Here the system is;

dxdt=x2-2y-3dydt=3x2-2xy

And the phase plane equation is;

dydx=3x2-2xyx2-2y-3

Step 2: Solve for exactness

Here the equation is dydx=3x2-2xyx2-2y-3.

(2xy-3x2)dx+(x2-2y-3)dy=0M=(2xy-3x2)N=(x2-2y-3)My=2x=Nx

Step 3: Find the value of F and G.

Now,

F(x,y)=M(x,y)dx+g(y)=(2xy-3x2)dx+g(y)=x2y-x3+g(y)N(x,y)=x2+g'(y)x2-2y-3=x2+g'(y)g'(y)=-2y-3g(y)=y-2+cF(x,y)=x3-x2y-y-2+c

Therefore, the solution is x3-x2y-y-2=c.

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