• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q8E

Expert-verified
Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 259
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

Sturm–Liouville Form. A second-order equation is said to be in Sturm–Liouville form if it is expressed as [p(t)y'(t)]'+q(t)y(t)=0. Show that the substitutions x1=y,x2=py' result in the normal form x'1=x2p,x2=-qx1. If y(0)=a,y'(0)=b are the initial values for the Sturm–Liouville problem, what are x1(0)andx2(0)?

x1(0)=ax2(0)=p(0)b

See the step by step solution

Step by Step Solution

Step 1: Express the equation in form of x

Here given. p(t)y'(t)'+q(t)y(t)=0

And

x1=y,x2=py'

The equation transforms as:

x'2+qx1=0x'2=-qx1y'=x2px'1=x2p

Step 2: The initial conditions.

The given initial conditions are y(0)=a,y'(0)=b.

Initial conditions after transformations;

x1(0)=ax2(0)=p(0)y'(0)=p(0)b

This is the required result.

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.