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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 1
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

In Problems 9–20, determine whether the equation is exact.

If it is, then solve it.

(2xy+3)dx+(x2-1)dy=0

The solution is y=C-3x/x2-1.

See the step by step solution

Step by Step Solution

Step 1: Evaluate whether the equation is exact

Here(2xy+3)dx+(x2-1)dy=0

The condition for exact isMy=Nx .

M(x,y)=2xy+3N(x,y)=x2-1My=2x=2x=Nx

This equation is exact.

Step 2: Find the value of F(x, y)

Here

M(x,y)=2xy+3F(x,y)=M(x,y)dx+g(y)=(2xy+3)dx+g(y)=x2y+3x+g(y)

Step 3: Determine the value of g(y)

Fy(x,y)=N(x,y)x2+g'(y)=x2-1g'(y)=-1g(y)=-y

NowF(x,y)=x2y+3x-y

x2y+3x-y=C(x2-1)y+3x=C(x2-1)y=C-3xy=(C-3x)/(x2-1)

Therefore, the solution isy=(C-3x)/(x2-1) y=(C-3x)/(x2-1)

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