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Q7.3 - 21E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 365
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Given that L{cosbt}(s)=s/(s2+b2), use the translation property to compute L{eatcosbt}.

The value of Leatcosbt is s-a(s-a)2+b2.

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Step by Step Solution

Define Laplace transform

When specific initial conditions are supplied, especially when the initial values are zero, the Laplace transform is a handy method of solving certain types of differential equations. Laplace transform Lof a function f(t) is defined as:

role="math" localid="1655792122645" L{f(t)}=0<>e-stf(t)dt

In words, we can describe this expression as the Laplace transform of f(t) equals function F of s, that is, L{f(t)}=F(s).

Find the value of Leatcosbt

Given that L{cosbt}(s)=s/s2+b2,

Find Leatcosbt(s) using to translation property Leatf(t)(s)=F(s-a) as:

Leatcosbt(s)=F(s-a)=L{cosbt}(s-a)=s-a(s-a)2+b2

Hence, the value of Leatcosbt is s-a(s-a)2+b2.

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