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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 180
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Find a particular solution to the differential equation.

2z''+z=9e2t

The particular solution of the given differential equation is zp(x)=e2t.

See the step by step solution

Step by Step Solution

Step 1: firstly, write the auxiliary equation of the given differential equation

The given differential equation is,

2z''+z=9e2t               (1)

Write the homogeneous differential equation of the equation (1),

2z''+z=0

The auxiliary equation for the above equation,

2m2+1=0

Step 2: Now find the roots of the auxiliary equation 

Solve the auxiliary equation,

2m2+1=0m2=-12m=±i12

The roots of the auxiliary equation are,

m1=i12,      m2=-i12

The complementary solution of the given equation is,

Zc(x)=c1cos12t+c2sin12t

Step 3: Final conclusion, find a particular solution to the differential equation

According to the method of undetermined coefficients, assume, the particular solution of equation (1),

zp(x)=Ae2t                     ......(2)

Now find the derivative of the above equation,

zp'(x)=2Ae2tzp''(x)=4Ae2t

From the equation (1),

2zp''+zp=9e2t2(4Ae2t)+Ae2t=9e2t9Ae2t=9e2tA=1

Substitute the value of A in the equation (2),

zp(x)=e2t

Therefore, the particular solution of equation (1),

zp(x)=e2t

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