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Q 3.3-11E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 108
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

During the summer the temperature inside a van reaches 55°C, while that outside is a constant 35°C. When the driver gets into the van, she turns on the air conditioner with the thermostat set at 16°C. If the time constant for the van is 1k=2hr and that for the van with its air conditioning system is 1k1=13hr, when will the temperature inside the van reach 27°C?

The temperature inside the van will reach 27°C after 38.04minutes.

See the step by step solution

Step by Step Solution

Step1: Given data.

The temperature inside a van is 55°C and that outside is a constant 35°C. When the driver gets into the van, she turns on the air conditioner with the thermostat set at 16°C. When the driver gets into the van, she turns on the air conditioner with the thermostat set at 16°C. Given the time constant for the van is 1k=2hr and that for the van with its air conditioning system is 1k1=13hr. It has to find the time after which the temperature inside the van will reach 27°C.

Step 2: Analyzing the given statement 

Here, temperature inside the van, Tin=550C.

Temperature outside the van, Tout=350C.

Temperature value on thermostat, Tt=160C.

The time constant for the van is 1k=2hr.

The time constant for the van with its air conditioning system is 1k1=13hr.

It will use the following formula to find the solution,

dTdt=K1Tout-T+KuTt-T …… (1)

Step 2: To find the value of Ku

As it knows that,

K1+Ku=K

Using values from step 1,

3+Ku=12Ku=12-3Ku=1-62Ku=-52

It will use this value in equation (1).

Step 3: To determine the time when the temperature inside the van will reach 27∘C

Now from equation (1),

dTdt=335-T-5216-TdTdt=130-T2dTdt=65-T2

i.e., dTdt+T2=65 …… (2)

Integrating factor =role="math" localid="1664179724944" e12dt=e12t

Multiplying both sides of (2) by e12t,

e12t·dTdt+e12t·T2=65·e12t ddtT·e12t=65·e12t

Integrating both sides,

T·e12t=130e12t+C Where, C is an arbitrary constant.

When t=0,T=55oC

55=130+CC=-75

Therefore,

When temperature is 27C

27=130-75e-12t27-130=-75e-12t 103=75e-12t t=2ln1.373 t=0.634hr t=38.04min

Hence, the temperature inside the van will reach role="math" localid="1664180086516" 27°C after role="math" localid="1664180100673" 38.04minutes.

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