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Q 3.5-2E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 121
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

An RC circuit with a 1Ω resistor and a 0.000001-F capacitor is driven by a voltage E(t)=sin100tV. If the initial capacitor voltage is zero, determine the subsequent resistor and capacitor voltages and the current.

The subsequent resistor is ER=-10-4cos100t+10-8sin100t-10-4e-106t.

The subsequent capacitor voltage is EC=-10-4cos100t+sin100t+10-4e-106t.

The subsequent current is I=-10-4cos100t+sin100t+10-4e-106t.

See the step by step solution

Step by Step Solution

Step 1: Important formula.

The governing differential equation for RC circuit is dqdt+qCR=ER.

Step 2: Determine the subsequent resistor.

The governing differential equation for RC circuit is dqdt+qCR=ER......(1).

Here q0=0,C=10-6,Et=sin100t.

Put these values in equation (1) then

dqdt+10-6q=sin100t

The integrating factor is e106t.

Now the equation is

e106tq=e106tsin100tdte106tq=-10-10e106tcos100t+10-6e106tsin100t+Cq(t)=10-10cos100t+10-6sin100t+Ce-106t

Now, find the value of done

I=e106tsin100tdt=-1100e106tcos100t+106100e106tcos100tdt=-1100cos100t+1000e106tcos100tdt=-1100e106tcos100t+1000(1100e106tsin100t-106100e106tsin100tdt)=-1100e106tcos100t+100(1100e106tsin100t-106100-10000I=-1100e106tcos100t+100e106tsin100t-100000000I+CI=-10-10e106cos100t+10-6sin100t+C

Apply the initial conditions then C=-10-10.

I=-10-10e106cos100t+10-6sin100t+-10-10qt=10-10cos100t+10-6sin100t-10-10e-106t

The subsequent resistor is EC=-10-4cos100t+sin100t+'10-4e-106t.

Step 3: evaluate capacitor voltage.

Now, find the value of capacitor voltage.

EC=qtCEC=10-10cos100t+10-6sin100t-10-10e-106t10-10EC=-10-4cos100t+sin100t+'10-4e-106t

The subsequent capacitor voltage is EC=-10-4cos100t+sin100t+'10-4e-106t

Step 4: Determine electric resistor.

Using Kirchhoff’s voltage law to the RC circuit

ER=EC-EtER=-10-4cos100t+10-8sin100t-10-4e-106t

Step 5: find the value of current.

Now, find the value of current.

I=ERRI=-10-4cos100t+sin100t+10-4e-106t

Therefore, the subsequent current is I=-10-4cos100t+sin100t+10-4e-106t.

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