• :00Days
  • :00Hours
  • :00Mins
  • 00Seconds
A new era for learning is coming soonSign up for free
Log In Start studying!

Select your language

Suggested languages for you:
Answers without the blur. Sign up and see all textbooks for free! Illustration

Q 3.5-3E

Expert-verified
Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 121
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

Answers without the blur.

Just sign up for free and you're in.

Illustration

Short Answer

The pathway for a binary electrical signal between gates in an integrated circuit can be modeled as an RC circuit, as in Figure 3.13(b); the voltage source models the transmitting gate, and the capacitor models the receiving gate. Typically, the resistance is 100Ω and the capacitance is very small, say, 10-12F (1 picofarad, pF). If the capacitor is initially uncharged and the transmitting gate changes instantaneously from 0 to 5 V, how long will it take for the voltage at the receiving gate to reach (say) ? (This is the time it takes to transmit a logical “1.”)

The time taken by the signal is t=9.163×10-11sec.

See the step by step solution

Step by Step Solution

Step 1: Important formula.

The governing differential equation for RC circuit is dqdt+qCR=ER

Step 2: Evaluate the value of  Qt

Here resistance (R)=100Ω, Capacitance (C)=10-12F , initial charge Qo=0 , voltage supplied to circuit (E)=5V.

Now the differential equation of RC circuit is

QC+IR=EdQdt+QRC=ER

Now the integrating factor is etRC .

The equation is

QetRC=etRCERdtQetRC=ECetkRCQ(t)=EC+ke-tRC

When t=0,Q=0 then k=-CE .

Q(t)=CE(1-e-tRC)

Step 3: Determine the value of  Qc

C=Qvcvc=QCvc=E(1-e-tRC)

Step 4: Find the value of time.

When solving for t and put the all required values then

t=-RCln(1-vcE)t=-(100)(10-12)ln(1-E(1-e-tRC)E)t=9.163×10-11sec

Therefore, the time taken by the signal is t=9.163×10-11sec.

Most popular questions for Math Textbooks

Icon

Want to see more solutions like these?

Sign up for free to discover our expert answers
Get Started - It’s free

Recommended explanations on Math Textbooks

94% of StudySmarter users get better grades.

Sign up for free
94% of StudySmarter users get better grades.