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Q3-3.4-16E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 116
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Find the equation for the angular velocity ω in Problem15, assuming that the retarding torque is proportional to role="math" localid="1663966970646" ω

The equation of angular velocity is (Kω-T lnT-Kω)=(Kωo-T lnT-Kωo)-K2t2I

See the step by step solution

Step by Step Solution

Step1: Find the equation for the angular velocity

Here the notations are T= torque for motor, ω= angular velocity, I = moment of inertia and ω0= initial angular velocity.

According To the question retarding torque due to friction is proportional to the angular velocity so, T1=-Kω (K is proportionality constant)

Now moment of inertia × angular velocity = sum of the torques

Idωdt=T-KωI T-Kω=dt Variable separating-2IωK-2IT lnT-KωK2=t+C Integrating on both sides2IK(ω-IT lnT-KωK)=t+C(ω-IT lnT-KωK)=-Kt2I+C1(Kω-T lnT-Kω)=-K2t2I+A

Step 2: Find the value of A

Put ω0=ω0 then value of A.

A=(Kωo-T lnT-Kωo)(Kω-T lnT-Kω)=(Kωo-TlnT-Kωo)-K2t2I

Hence, the equation of angular velocity is (Kω-T lnT-Kω)=(Kωo-T lnT-Kωo)-K2t2I.

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