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Q3.2-13E
Expert-verifiedIn Problem 9, suppose we have the additional information that the population of splake in 2004 was estimated to be 5000. Use a logistic model to estimate the population of splake in the year 2020. What is the predicted limiting population? [Hint: Use the formulas in Problem 12.
The estimated population of splake in the year 2020 is 5970 and the predicted limiting population is 6000.
Given, that in 1990, the population of splake in the lake was 1000 and it was estimated to be 3000 in 1997 and 5000 in 2004. We have to find estimated population of splake in the year 2020 and the predicted limiting population.
Here, we have initial population,
(Because, 1997-1990=7)
(Because, 2004-1990=14)
We will use the following formula to find the estimated population of splake in the year 2020,
To find the values of p1 and A, we will use the following formulas from problem 12,
One will find the values of and A, using the formulas from equation (2 and 3),
We will use these values of p1 and A in equation (1) to find the estimated population of splake in the year 2020.
To find the estimated population of splake in the year 2020, we will substitute t=30 and other values from step1 and step3,
Hence, the estimated population of splake in the year 2020 is 5970.
Thus, the predicted limiting population is 6000.
Local versus Global Error. In deriving formula (4) for Euler’s method, a rectangle was used to approximate the area under a curve (see Figure 3.14). With
\({\bf{g(t) = f(t,f(t))}}\) , this approximation can be written as \(\int\limits_{{{\bf{x}}_{\bf{n}}}}^{{{\bf{x}}_{{\bf{n + 1}}}}} {{\bf{g(t)dt}} \approx {\bf{hg(}}{{\bf{x}}_{\bf{n}}}{\bf{)}}} \)where \({\bf{h = }}{{\bf{x}}_{{\bf{n + 1}}}}{\bf{ - }}{{\bf{x}}_{\bf{n}}}\) .
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