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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 450
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Aging spring without damping. In a mass-spring system of aging spring discussed in Problem 30, assume that there is no damping (i.e., b=0), m=1 and k=1. To see the effect of aging consider as positive parameter.

(a) Redo Problem 30 with b=0 and η arbitrary but fixed.

(b) Set η =0 in the expansion obtained in part (a). Does this expansion agree with the expansion for the solution to the problem with η=0. [Hint: When η =0 the solution is x(t)=cos t].

(a) The first four nonzero terms are x(t)=1-1/2t2+η/6 t3+(1-η2)/24 t4+... .

(b) Yes, this expansion agree with the expansion with η =0.

See the step by step solution

Step by Step Solution

Define power series expansion:

The power series approach is used in mathematics to find a power series solution to certain differential equations. In general, such a solution starts with an unknown power series and then plugs that solution into the differential equation to obtain a recurrence relation for the coefficients.

A differential equation's power series solution is a function with an infinite number of terms, each holding a different power of the dependent variable.

It is generally given by the formula,

y(x)=Σn=0 anxn

(a) Find the expression:

Let,

x(t)=Σn=0 antn

Taking derivative of the above equation,

x'(t)=Σn=1 nantn-1

x"(t)=Σn=2 n(n-1)antn-2

The Maclaurin series is,

e-ηt=∑n=0(-ηt)/n!

=∑n=0(η)n/n! tη

Replace this in the equation.

n=2 n(n+1)antn-2+ ∑n=0(η)n/n! tη n=0an tη=0

You will set coefficients equal to zero. The expression is,

2a2+a0=0

a2=-a0/2

Hence the expression is a2=-a0/2.

Find the first four nonzero terms:

Now we have to find the coefficients.

a2=-1/2

6a3 -ηa0+a1=0

a3=(ηa0-a1)/6

=η/6

(-η)2/2! a0+(-η)1/1! a1+(-η)0/0! a22/2-ηa1+a2

12a42/2-ηa1+a2=0

a4= (-η2/2a0+η a1-a2)/12

=1-η2/24

Substitute the value of coefficients in the expression.

x(t)=1-1/2t2+η/6 t3+(1-η2)/24 t4+...

Hence the first four terms are x(t)=1-1/2t2+η/6 t3+(1-η2)/24 t4+... .

(b) Find whether this expansion agree with the expansion with η =0:

For η =0 the given equation is,

x"+x=0

The solution is

x(t)=cos t

From part (a) the solution will be,

x(t)=1-1/2t2+1/24t4+...

Since this is a Taylor’s series for cos t the expansion in part (a) agrees with the expansion in part (b).

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