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Q23E

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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 337
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

use the annihilator method to determinethe form of a particular solution for the given equation y''-5y'+6y=e3x-x2

y''-5y'+6y=e3x-x2

See the step by step solution

Step by Step Solution

Step 1: Solve the homogeneous of the given equation

The homogeneous of the given equation is

D2-5D+6[y]=(D-2)(D-3)[y]=0

The solution of the homogeneous is

yh(x)=c1e2x+c2e3x (1)

Let g(x)=e3x

Then

(D-3)[g]=0

Let h(x)=x2

Then

D3[h]=0

Hence

D3(D-3)[g-h]=0

Then, every solution to the given nonhomogeneous equation also satisfies

. D3(D-3)(D-2)(D-3)[y]=D3(D-2)(D-3)2[y]=0

Then

y(x)=c1e2x+c2e3x+c3xe3x+c4+c5x+c6x2 (2)

is the general solution to this homogeneous equation

We know u(x)=uh+up

Comparing (1) & (2)

yp(x)=c3xe3x+c4+c5x+c6x2

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