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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 332
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

Find a general solution for the differential equation with x as the independent variable.6z'''+7z''-z'-2z=0

Thus, the general solution to the given differential equation is;

z=C1e-x+C2ex2+C3e-2x3
See the step by step solution

Step by Step Solution

Step 1: Write the auxiliary equation.

The given differential equation is;

6z'''+7z''-z'-2z=0

The auxiliary equation is .6m3+7m2-m-2=0

Simplify the auxiliary equation.

6m3+7m2-m-2=06m3+7m2-m-2=0(m+1)(6m2+m-2)=0

One of the roots is . m1=-1

Find the other roots of the auxiliary equation by solving the quadratic equation.

m=-1±1+4(12)12m=-1±4912m=-1±712m=-1+712,-1-712m2=12,m3=-23

Step 2: Write the general solution.

The roots are real and distinct; therefore the general solution to the given differential equation is given as:

z=C1em1x+C2em2x+C3em3xz=C1e(-1)x+C2e(12)x+C3e(-23)xz=C1e-x+C2ex2+C3e-2x3

Thus, the general solution to the given differential equation is;

z=C1e-x+C2ex2+C3e-2x3

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