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Fundamentals Of Differential Equations And Boundary Value Problems
Found in: Page 337
Fundamentals Of Differential Equations And Boundary Value Problems

Fundamentals Of Differential Equations And Boundary Value Problems

Book edition 9th
Author(s) R. Kent Nagle, Edward B. Saff, Arthur David Snider
Pages 616 pages
ISBN 9780321977069

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Short Answer

use the method of undetermined coefficients to determine the form of a particular solution for the given equation.

y'''+y''-2y=xex+1

yp(x)=-425xex+110x2ex-12

See the step by step solution

Step by Step Solution

Step 1: Find the corresponding auxiliaryequation

Theauxiliary equationof corresponding homogeneous equation

r3+r2-2=(r-1)r2+2r+2=0

The solutions of the auxiliary equation are

r=-1+i,r=-1-i,r=1

Step 2: Find particular solution

Let the particular solution be

yp(x)=axex+bx2ex+c

Then

yp'(x)=aex+(a+2b)xex+bx2exyp''(x)=(2a+2b)ex+(a+4b)xex+bx2exyp'''(x)=(3a+6b)ex+(a+6b)xex+bx2ex

Then

yp'''(x)+yp''(x)-2yp(x)=(3a+6b)ex+(a+6b)xex+bx2ex+(2a+2b)ex+(a+4b)xex+bx2ex-2axex-2bx2ex-2c=(5a+8b)ex+10bxex-2c

If (5a+8b)ex+10bxex-2c=xex+1

Then 5a + 8b = 0,10b = 1 and - 2c = 1

Then a=-425,b=110 andc=-12

Hence yp(x)=-425xex+110x2ex-12

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