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Q12.

Expert-verifiedFound in: Page 431

Book edition
Student Edition

Author(s)
Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages
227 pages

ISBN
9780395977279

**Find the area of each figure:**

**An equilateral triangle with perimeter****.18**

The area of given figure is$9\sqrt{3}$ square units.

Let the common sides be x

We know that in equilateral triangle all three sides are equal in length.

The perimeter of equilateral triangle18, which means the sum of all three sides will be equal to 18

$x+x+x=18$

$3x=18$

$x=6$

Thus, the sides of triangle are

$6,6,6$

Area of an equilateral triangle can be found using the formula

$A=\frac{\sqrt{3}}{4}{a}^{2}$

Where,

a=The sides of triangle.

$A=\frac{\sqrt{3}}{4}{a}^{2}$

$=\frac{\sqrt{3}}{4}{\left(6\right)}^{2}$

$=\sqrt{3}\times 3\times 3$

$=9\sqrt{3}$ Square units.

Therefore, the area of given figure is$9\sqrt{3}$ square units.

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