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Q3

Expert-verified
Found in: Page 41

Geometry

Book edition Student Edition
Author(s) Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Pages 227 pages
ISBN 9780395977279

Justify each step.$\frac{z+7}{3}=-11$ $z+7=-33$ $z=-40$

$\frac{z+7}{3}=-11$ Given

$z+7=-33$ Multiplication property of equality

$z=-40$ Subtraction property of equality

See the step by step solution

Step 1. Apply the multiplication property of equality.

If $a=b$, then $ca=cb$.

Step 2. Description of step.

Multiply each side of $\frac{z+7}{3}=-11$ by 3 and simplify.

$\begin{array}{c}3×\frac{z+7}{3}=3×\left(-11\right)\\ z+7=-33\end{array}$

Step 3. Apply the subtraction property of equality.

If $a=b$ and $c=d$, then $a-c=b-d$.

Step 4. Description of step.

Subtract 7 from each side of the equation obtained in step 2 to find the value of z.

$\begin{array}{c}z+7-7=-33-7\\ z=-40\end{array}$

Therefore, the value of z is $-40$.