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Q4.

Expert-verifiedFound in: Page 292

Book edition
Student Edition

Author(s)
Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages
227 pages

ISBN
9780395977279

**Find the value of $x$ from the given figure.**

The value of $x$ is $2\sqrt{10}$.

The two sides are given 9 and 11.

We use Pythagorean Theorem.

Pythagorean Theorem state that in a right angle triangle, the square of the hypotenuse is equal to the sum of squares of other sides.

Substitute the values and calculate.

$\begin{array}{c}{9}^{2}+{x}^{2}={11}^{2}\\ 81+{x}^{2}=121\\ {x}^{2}=40\end{array}$

Taking square root we get.

$\begin{array}{l}x=\pm \sqrt{40}\\ x=\pm 2\sqrt{10}\end{array}$

Since, distance is a positive quantity so we neglect negative sign.

Therefore, the value of $x$ is $2\sqrt{10}$.

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