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Q3.

Expert-verifiedFound in: Page 243

Book edition
Student Edition

Author(s)
Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Pages
227 pages

ISBN
9780395977279

**ABCD is a parallelogram. Find the value of each ratio.**

$m\angle C:m\angle D$

The simplest form of $m\angle C:m\angle D=1:5$

According to the given figure is,

In parallelogram,

$\begin{array}{l}m\angle C={30}^{\circ}\\ m\angle D={150}^{\circ}\end{array}$

Write the ratio,

$\begin{array}{l}m\angle C:m\angle D=30:150\\ \frac{m\angle C}{m\angle D}=\frac{30}{150}\end{array}$

To write the fraction in simplest form, divide the numerator and denominator with the GCF (Greatest Common Factor).

Write the prime factors of numerator and denominator.

** $\begin{array}{l}30=2\times 3\times 5\\ 150=2\times 3\times 5\times 5\end{array}$**

Here GCF is.$2\times 3\times 5=30$

Here we will divide the numerator and denominator by30 v.

$\frac{30}{150}=\frac{30/30}{150/30}=\frac{1}{5}$

** **Therefore, the simplest form of the given ratio is$m\angle C:m\angle D=1:5$.

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