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Answers without the blur. Sign up and see all textbooks for free! Q.13.2

Expert-verified Found in: Page 752 ### Introductory Statistics

Book edition OER 2018
Author(s) Barbara Illowsky, Susan Dean
Pages 902 pages
ISBN 9781938168208 # MRSA, or Staphylococcus aureus, can cause a serious bacterial infections in hospital patients. Table 13.6 shows various colony counts from different patients who may or may not have MRSA. The data from the table is plotted in Figure 13.5. Conc$=0.6$Conc$=0.8$Conc$=1.0$Conc$=1.2$Conc$=1.4$91622302766931471991689882120148132Plot of the data for the different concentrations: Test whether the mean number of colonies are the same or are different. Construct the ANOVA table (by hand or by using a $TI-83,{83}^{+},or84$ calculator), find the p-value, and state your conclusion. Use a $5%$ significance level.

According to the output, the P-value is $.79$. So, at the $5%$ level of significance null hypothesis will be accepted. Thus, mean number of bacterial infections in hospitals were same for the various colony counts from different patients.

See the step by step solution

## Step-1 Given Information

MRSA, or Staphylococcus aureus, can cause a serious bacterial infections in hospital patients. Table shows various colony counts from different patients who may or may not have MRSA :

 Conc$=0.6$ Conc$=0.8$ Conc$=1.0$ Conc$=1.2$ Conc$=1.4$ 9 16 22 30 27 66 93 147 199 168 98 82 120 148 132

## Step-2 Explanation

Consider the following Data of various colony counts from different patients to check the mean number of bacterial infections in hospitals were same

 Conc$=0.6$ Conc$=0.8$ Conc$=1.0$ Conc$=1.2$ Conc$=1.4$ 9 16 22 30 27 66 93 147 199 168 98 82 120 148 132

To check the mean number of number of bacterial infections in hospitals were same, use $Ti-83$calculator. For this, click on STAT$\to$ press1$\to$EDIT, then put data into the list${L}_{1},{L}_{2},{L}_{3},{L}_{4},{L}_{5}$. The screenshot is given as below: Now Again press STAT $\to$ arrow over the TESTS $\to$ arrow down to ANOVA $\to$ Press var then select1, press var then select 2, press var then select 3, press var then select 4 and press var then select 5 to fill the values of ${L}_{1},{L}_{2},{L}_{3,}{L}_{4},{L}_{5}$. The screen shot is given as below: Press ENTER the screenshot of output is given below: According to the output, the P-value is $.79$. So, at the $5%$ level of significance null hypothesis will be accepted. Thus, mean number of bacterial infections in hospitals were same for the various colony counts from different patients. ### Want to see more solutions like these? 