Book edition OER 2018

Author(s) Barbara Illowsky, Susan Dean

Pages 902 pages

ISBN 9781938168208

Answers without the blur.

Just sign up for free and you're in.

Short Answer

Identify the potential outlier in the scatter plot. The standard deviation of the residuals or errors is approximately 8.6

82 are more than two standard deviations from 58 which makes coordinate $(6, 58)$ as a potential outlier.

See the step by step solution

Step by Step Solution

TABLE OF CONTENTS :

TABLE OF CONTENTS

Step 1: Given information

Given in the question is a graph

Step 2: Solution

The outlier is clearly separated from the least-squares regression line in the question.

That is, the outlier on the graph is at point $(6, 58)$

Hence the predicted value is $82 .$

It may be deduced that $58$ is $24$ units less than $82$ .

As a result, $24$ exceeds two standard deviations.

$2 s = 2 \times 8.6$

$= 17.2$

Find Study Materials for

Create Study Materials

Select your language

Introductory Statistics

Answers without the blur.

Short Answer

Identify the potential outlier in the scatter plot. The standard deviation of the residuals or errors is approximately 8.6

Step by Step Solution

Step 1: Given information

Step 2: Solution

Most popular questions for Math Textbooks

Want to see more solutions like these?

Recommended explanations on Math Textbooks

Select your language

Introductory Statistics

Answers without the blur.

Short Answer

Identify the potential outlier in the scatter plot. The standard deviation of the residuals or errors is approximately 8.6

Step by Step Solution

Step 1: Given information

Step 2: Solution

Most popular questions for Math Textbooks

Want to see more solutions like these?

Recommended explanations on Math Textbooks

Decision Maths

Calculus

Probability and Statistics

Statistics

Mechanics Maths

Geometry

Pure Maths