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Q. 15

Expert-verifiedFound in: Page 428

Book edition
OER 2018

Author(s)
Barbara Illowsky, Susan Dean

Pages
902 pages

ISBN
9781938168208

Find the percentage of sums between 1.5 standard deviations below the mean and one standard deviation above the mean.

MEAN is used to calculate the entire data in statistical terms.

Explanation:

The sample size of forty is randomly drowned from cholesterol with mean$180$ and standard deviation$20$. The mean of sums is given as:

$\sum X=\left(n\right)\left({\mu}_{X}\right)-\left(z\right)\left(\sqrt{n}\right)\left({\sigma}_{X}\right)$

$7326.49$

The sum that is$1.5$ the standard deviation below the mean of the $7010.26$sum is given as;

$\mathrm{\Sigma}X=\left(n\right)\left({\mu}_{X}\right)-\left(z\right)\left(\sqrt{n}\right)\left({\sigma}_{X}\right)$

$7010.26$

The percentage for the sums between the standard deviation below the mean of sums and the standard deviation above the mean of the sum is 77.45%.

The percentage for the given standard deviation is 77.45%.

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