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Introductory Statistics
Found in: Page 426
Introductory Statistics

Introductory Statistics

Book edition OER 2018
Author(s) Barbara Illowsky, Susan Dean
Pages 902 pages
ISBN 9781938168208

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Short Answer

What is the mean, standard deviation, and sample size?

The mean time for each review is 4 hours and standard deviation is 1.2 hours and sample size is 16 .

See the step by step solution

Step by Step Solution

Step 1:  Given information 

Given in the question that, Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2 hours. Let Χ be the random variable representing the time it takes her to complete one review. Assume Χ is normally distributed. Let x¯{"x":[[4,22,36],[6,35],[4.777605574440839,5.647456684472792,6.517307794504744,8.257010014568648,9.1268611246006,9.996712234632552,10.866563344664504,11.736414454696456,12.606265564728409,13.476116674760362,14.345967784792315,15.215818894824267,16.08567000485622,16.95552111488817,17.825372224920123,18.695223334952075,19.565074444984027,20.43492555501598,21.30477666504793,22.174627775079884,23.044478885111836,23.914329995143788,24.78418110517574,25.654032215207693,26.523883325239645,27.393734435271597,28.26358554530355,29.1334366553355,30.003287765367453,30.873138875399405,31.742989985431358,32.61284109546331]],"y":[[9,59,116],[115,9],[-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313,-4.478535472460313]],"t":[[0,0,0],[0,0],[1648618415293,1648618415612,1648618415620,1648618415654,1648618415671,1648618415686,1648618415706,1648618415728,1648618415751,1648618415770,1648618415787,1648618415805,1648618415826,1648618415870,1648618415887,1648618415904,1648618415931,1648618415970,1648618415993,1648618416037,1648618416065,1648618416085,1648618416142,1648618416182,1648618416221,1648618416237,1648618416262,1648618416330,1648618416379,1648618416400,1648618416436,1648618416488]],"version":"2.0.0"}be the random variable representing the mean time to complete the 16 reviews. Assume that the 16 reviews represent a random set of reviews.

Step 2: Explanation

According to the supplied facts, the manager reviews 16 employees each month. And reviews time is approximately 4 hours for each review with a population standard deviation of 1.2 hours. Thus, the meantime for each review is 4 hours and the standard deviation is 1.2 hours, and sample size is 16 .

Step 3: Final answer

The meantime for each review is 4 hours and the standard deviation is 1.2 hours, and sample size is 16 .

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