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Linear Algebra and its Applications
Found in: Page 165
Linear Algebra and its Applications

Linear Algebra and its Applications

Book edition 5th
Author(s) David C. Lay, Steven R. Lay and Judi J. McDonald
Pages 483 pages
ISBN 978-03219822384

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Short Answer

Let \(A = \left[ {\begin{array}{*{20}{c}}3&1\\4&2\end{array}} \right]\). Write \(5A\). Is \(\det 5A = 5\det A\)?

\(\det 5A \ne 5\det A\)

See the step by step solution

Step by Step Solution

Step 1: Determine the matrix \(5A\)

Let \(A = \left[ {\begin{array}{*{20}{c}}3&1\\4&2\end{array}} \right]\).

Compute the matrix \(5A\) as shown below:

\(\begin{array}{c}5A = 5\left[ {\begin{array}{*{20}{c}}3&1\\4&2\end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}}{15}&5\\{20}&{10}\end{array}} \right]\end{array}\)

Step 2: Verify whether \(\det 5A = 5\det A\) 

The determinant of matrix A is shown below:

\(\begin{array}{c}\det A = \left| {\begin{array}{*{20}{c}}3&1\\4&2\end{array}} \right|\\ = 6 - 4\\ = 2\end{array}\)

The determinant of matrix \(5A\) is shown below:

\[\begin{array}{c}\det 5A = \left| {\begin{array}{*{20}{c}}{15}&5\\{20}&{10}\end{array}} \right|\\ = 150 - 100\\ = 50\end{array}\]

Thus, \(\det 5A \ne 5\det A\).

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